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Similar Triangles: â–³ ZUW ~ â–³ ZWY ~ â–³ WUY
Measures: WZ=30 and UZ=18
Let's review the theorems that can help us prove that two triangles are similar.
With this in mind, we will identify the similar triangles and find the measures, one at a time.
We want to identify similar triangles in the given diagram. We will consider two pairs of triangles at a time.
Let's separate these triangles. Be aware that by the Reflexive Property of Congruence, ∠Z is congruent to itself.
In the diagram above we can see that ∠UWZ and ∠WYZ are congruent angles, and that ∠WZU and ∠YZW are also congruent angles. This means that △ ZUW and △ ZWY have two pairs of congruent angles. Therefore, by the Angle-Angle Similarity Theorem, these two triangles are similar.
To get these two triangles, we will divide the main triangle along the height. Notice that ∠ZUW and ∠WUY form a linear pair. Therefore, they are supplementary angles. Since ∠ZUW is a right angle, so is ∠WUY. This means that they are congruent angles.
Also, ∠UWZ and ∠UYW are marked as congruent angles. Again, by the Angle-Angle Similarity Theorem, these triangles are similar. △ ZUW ~ △ WUY
We found that △ ZUW and △ ZWY are similar triangles. We also found that △ ZUW and △ WUY are similar triangles as well. Therefore, by the Transitive Property of Similarity, △ ZWY and △ WUY are similar triangles. △ ZUW ~ △ ZWY △ ZUW ~ △ WUY ⇓ △ ZWY ~ △ WUY This means that there are three similar triangles in the given diagram. △ ZUW ~ △ ZWY ~ △ WUY
Knowing that â–³ ZUW and â–³ ZWY are similar triangles, we can identify corresponding sides in these triangles.
Let's state the pairs of corresponding sides. ccc UZ & WZ & UW and & and & and WZ & YZ & WY Recall that corresponding sides of similar figures have proportional lengths. We are given expressions for the lengths of these sides which we can use to write a proportion. UZ/WZ = WZ/YZ = UW/WY ⇓ x+6/3x-6 = 3x-6/( x+6)+ 32 = UW/40 First, we can find UW using the two already known side lengths of △ WUY and the Pythagorean Theorem.
Note that, when solving the equation, we only kept the principal root. This is because a side length can never be negative! We can now substitute UW= 24 in the equation 3x-6( x+6)+ 32 = UW 40, and solve for x.
UW= 24
Remove parentheses
Add terms
a/b=.a /8./.b /8.
LHS * (x+38)=RHS* (x+38)
LHS * 5=RHS* 5
Distribute 5
Distribute 3
LHS-3x=RHS-3x
LHS+30=RHS+30
.LHS /12.=.RHS /12.
Now that we know the value of x, we can find WZ and UZ. To do so, we will substitute x= 12 in the expressions for the lengths.
| Measure | Expression | Substitute | Simplify |
|---|---|---|---|
| WZ | 3x-6 | 3(12)-6 | 30 |
| UZ | x+6 | 12+6 | 18 |
We found that WZ=30 and UZ=18.