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Use the Polygon Angles Sum Theorem.
See solution.
We are asked to prove Theorem 6.10.
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Theorem 6.10 |
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If both pairs of opposite angles of a quadrilateral are congruent, then the quadrilateral is a parallelogram. |
Let's label the congruent opposite angles on the diagram.
Recall that if the measure of two angles add to 180, then these angles are called supplementary. Let's focus on two angles like this. We know that AB is a transversal to AD and BC, and angles ∠A and ∠B are consecutive interior angles.
Since angles ∠A and ∠B are supplementary, the Consecutive Interior Angles Converse Theorem guarantees that AD and BC are parallel. We can also look at a different pair of angles.
Angles ∠A and ∠D are also supplementary consecutive interior angles, so segments AB and DC are also parallel. Since the opposite sides of ABCD are parallel, by definition, it is a parallelogram. We can summarize the argument above in a paragraph proof.
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&Given:&&Both pairs of opposite angles
& &&of a quadrilateral are congruent.
&Prove:&&The quadrilateral is a parallelogram.
Proof.
Since opposite angles have the same measure and the sum of the angle measures in a quadrilateral is 360, the sum of the measures of any two consecutive angles is 180. Applying the Consecutive Interior Angles Converse Theorem for the supplementary consecutive interior angles ∠A and ∠B, we get that segments AD and BC are parallel. Using supplementary consecutive interior angles ∠A and ∠D, we also get that segments AB and DC are parallel. Since opposite sides are parallel, by definition, ABCD is a parallelogram.