McGraw Hill Glencoe Geometry, 2012
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McGraw Hill Glencoe Geometry, 2012 View details
3. Tests for Parallelograms
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Exercise 30 Page 419

See solution.

Practice makes perfect

We are asked to prove Theorem 6.10.

Theorem 6.10

If both pairs of opposite angles of a quadrilateral are congruent, then the quadrilateral is a parallelogram.

Let's label the congruent opposite angles on the diagram.

We can use that the angle measures of a quadrilateral add to 360 to find the sum of x and y.
m∠ A+m∠ B+m∠ C+m∠ D=360
x+y+x+y=360
Simplify
2x+2y=360
2(x+y)=360
x+y=180
Recall that if the measure of two angles add to 180, then these angles are called supplementary. Let's focus on two angles like this. We know that AB is a transversal to AD and BC, and angles ∠ A and ∠ B are consecutive interior angles.

Since angles ∠ A and ∠ B are supplementary, the Consecutive Interior Angles Converse Theorem guarantees that AD and BC are parallel. We can also look at a different pair of angles.

Angles ∠ A and ∠ D are also supplementary consecutive interior angles, so segments AB and DC are also parallel. Since the opposite sides of ABCD are parallel, by definition, it is a parallelogram. We can summarize the argument above in a paragraph proof.

Completed Proof

2 &Given:&&Both pairs of opposite angles & &&of a quadrilateral are congruent. &Prove:&&The quadrilateral is a parallelogram. Proof.

Since opposite angles have the same measure and the sum of the angle measures in a quadrilateral is 360, the sum of the measures of any two consecutive angles is 180. Applying the Consecutive Interior Angles Converse Theorem for the supplementary consecutive interior angles ∠ A and ∠ B, we get that segments AD and BC are parallel. Using supplementary consecutive interior angles ∠ A and ∠ D, we also get that segments AB and DC are parallel. Since opposite sides are parallel, by definition, ABCD is a parallelogram.