McGraw Hill Glencoe Geometry, 2012
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McGraw Hill Glencoe Geometry, 2012 View details
3. Tests for Parallelograms
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Exercise 35 Page 419

The given figure is a parallelogram, so both pairs of opposite sides are parallel and congruent.

Example Solution: A(0,0), B(a+b,0), C(a,c), D(- b,c)

Practice makes perfect

We are asked to name the missing coordinates for the given parallelogram.

Because we are told that the given figure is a parallelogram, we know that AB and DC are parallel. This means that they have the same slope. Let’s use the Slope Formula to calculate the slope of AB. Slope ofAB: 0- 0/(a+b)- 0 = 0

Since the slope of DC must also be 0, there cannot be a change in the y-value between its endpoints. Therefore, we know that the y-coordinate of D is also c.

Moreover, we know that opposite sides are congruent. This means that AB and DC have the same length. Let's calculate AB, the length of AB. AB: a+b- 0=a+b Therefore, DC must also be a+b. Let's add the obtained information to our diagram.

We can see above that if we add the x-coordinate of D and the side length a+b, we obtain the x-coordinate of C. Let - b be the x-coordinate of D. x-coordinate ofC: - b+a+b=a We found that possible coordinates for the given parallelogram are A( 0, 0), B( a+b, 0), C(a, c), and D(- b, c).

Note that this is just one possible solution. Other coordinates also make the figure a parallelogram.