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Consider that vertical angles are congruent.
m∠JLK=20
In a previous exercise, we found that m∠LPM=m∠LMP=80.
Substitute values
Add terms
LHS-160=RHS-160
Now that we found m∠MLP, we can find m∠JLK. Notice that ∠JLK and ∠MLP are vertical angles, which means that they are congruent. Then, m∠JLK=m∠MLP.
Therefore, m∠JLK is 20.
Analyzing the diagram, it can be observed that ∠1 and ∠2 form a straight angle, so these are supplementary angles. Similarly, ∠2 and ∠3 are also supplementary angles.
Therefore, by the Angle Addition Postulate, the sum of m∠1 and m∠2 is 180^(∘), and the sum of m∠2 and m∠3 is also 180^(∘). These facts can be used to express m∠2 in terms of m∠1 and also in terms of m∠3.
| Angle Addition Postulate | Isolate m∠2 |
|---|---|
| m∠1+m∠2 = 180^(∘) | m∠2 = 180^(∘)-m∠1 |
| m∠2+m∠3 = 180^(∘) | m∠2 = 180^(∘)-m∠3 |
By the Transitive Property of Equality, the expressions representing m∠2 can be set equal to each other. m∠2= 180^(∘)-m∠1 m∠2= 180^(∘)-m∠3 ⇓ 180^(∘)-m∠1= 180^(∘)-m∠3 Then the obtained equation can be simplified.
LHS-180^(∘)=RHS-180^(∘)
LHS * (- 1)=RHS* (- 1)
By the definition of congruent angles, this means that the vertical angles ∠1 and ∠3 are congruent angles. Using the same argumentation, ∠2 and ∠4 can also be proven to be congruent.