body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

McGraw Hill Glencoe Geometry, 2012

MH

McGraw Hill Glencoe Geometry, 2012 View details

3. Distance and Midpoints

Continue to next subchapter

Exercise 10 Page 30

Use the Midpoint Formula.

$(5.5, 0)$

Practice makes perfect

To find the midpoint, we can use the Midpoint Formula.

(\frac{x _{1} + x _{2}}{2}, \frac{y _{1} + y _{2}}{2})

The coordinates of the given endpoints are

M (7, 1)

and

N (4, - 1) .

Let's use these to find the coordinates of the midpoint.

(\frac{x _{1} + x _{2}}{2}, \frac{y _{1} + y _{2}}{2})

SubstitutePoints

Substitute $(7, 1)$ & $(4, - 1)$

(\frac{7 + 4}{2}, \frac{1 + ( - 1 )}{2})

$a + (- b) = a - b$

(\frac{7 + 4}{2}, \frac{1 - 1}{2})

Add and subtract terms

(\frac{1 1}{2}, \frac{0}{2})

Calculate quotient

(5.5, 0)

The midpoint is located at

(5.5, 0) .

Let's graph the given endpoints and the midpoint of the segment.

Subchapter links

Check Your Understanding p.30-31

Practice and Problem Solving p.31-34

H.O.T. Problems p.34

Standardized Test Practice p.35

Spiral Review p.35

Skills Review p.35