McGraw Hill Glencoe Algebra 1, 2012
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McGraw Hill Glencoe Algebra 1, 2012 View details
6. Systems of Inequalities
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Exercise 26 Page 374

Practice makes perfect
a Let h be the number of hours that Josefina works in a week and d be the amount of money that she earns in that week. Since we know that she works at least 10 and at most 30 hours in a week, we can write a compound inequality to represent it.

10 ≤ h ≤ 30 Since she earns $6.50 per hour and she can earn tips, if she works h hours in a week she will earn at least 6.5h that week. d ≥ 6.5h If we combine the inequalities, we get a system of inequalities. 10 ≤ h ≤ 30 d≥ 6.5 h

b The number of hours that Josefina works in a week is the independent variable h, and the money that she earns in a week is the dependent variable d. We want to graph the system of inequalities.
10 ≤ h ≤ 30 & (I) d≥ 6.5 h & (II) Consider the first inequality. 10≤ h ≤ 30 The solution set of this inequality contains all points which are between vertical lines h=10 and h=30. Since the inequalities signs are non-strict, both lines are solid.

Let's graph the boundary line of the second inequality, d = 6.5h.

Since the inequality d ≥ 6.5h has a non-strict sign, the line d = 6.5h is solid. To determine which half of plane we should shade, we will use a test point.

It looks like the point ( 10, 150) would be a good test point. We will substitute this point for h and d in the given inequality and simplify. If the substitution creates a true statement, we shade the same region the test point. Otherwise, we shade the opposite region.
d≥ 6.5h
150? ≥6.5( 10)
150 ≥ 65 ✓
We will shade the region that contains the test point, which is above the boundary line.

The overlapping portion of the inequalities is the solution set of the system of inequalities.

c Suppose Josefina worked x hours in that week. With tips she should earn 6.5x+17.5 dollars for the week. It is given that she earned a total of $ 180 in total in that week. We can equate these values.
6.5x+17.5=180 To find how many hours she worked that week, we will isolate x in this equation.
6.5x+17.5=180
6.5x=162.5
x=25
Josefina worked 25 hours that week.