McGraw Hill Glencoe Algebra 1, 2012
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McGraw Hill Glencoe Algebra 1, 2012 View details
6. Systems of Inequalities
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Exercise 36 Page 375

Practice makes perfect
a Let n be the number of notebooks sold per week and let p be the number of pens sold per week. The students would like to sell at least 20 notebooks and 50 pens per week. Therefore, n must be greater than or equal to 20, and p must be greater than or equal to 50.

n ≥ 20 and p ≥ 50 The price of one notebook is $2.50. Therefore, the expression 2.5n represents the amount earned by selling notebooks. Similarly, since the price of one pen is $1.25, the expression 1.25p represents the amount earned by selling pens. We are told the goal is earning at least $60. 2.5n+1.25p ≥ 60 We can combine the three inequalities we have written to form a system of inequalities. n ≥ 20 & (I) p ≥ 50 & (II) 2.5n+1.25p≥ 60 & (III)

b Let the horizontal axis be the n-axis and the vertical axis be the p-axis. Let's graph the inequalities one at a time.

Inequality (I)

To obtain the boundary line we replace the inequality sign with an equals sign. ccc Inequality & & Boundary Line n ≥ 20 & & n = 20 The line n=20 is a vertical line which passes through (20,0). Since the inequality is not strict the line will be solid. The inequality states that n is greater than or equal to 20. Therefore, we will shade the half-plane to the right of the line.

Inequality (II)

The boundary line related to the second inequality is p=50. This is a horizontal line whose y-intercept is 50. Since p is greater than or equal to 50, we will shade the region above the line. It will be solid because the inequality is not strict.

Inequality (III)

To draw the third inequality, let's isolate p.
2.5n+1.25p ≥ 60
â–Ľ
Solve for p
1.25p ≥ 60-2.5n
p ≥ 60-2.5n/1.25
p ≥ 60/1.25-2.5n/1.25
p ≥ 60/1.25-2.5/1.25n
p ≥ 48-2n
p ≥ - 2n+48
Now we consider the boundary line. ccc Inequality & & Boundary Line p ≥ - 2n+48 & & p = - 2n+48 Note that the line is written in slope-intercept form. To graph it we will plot its y-intercept 48 and use the slope - 2 to find another point on the line. Then we will connect these points with a straight edge. The line will be solid, because the inequality is not strict.
To determine the half-plane we should shade we will test a point. If substituting the coordinates of this point into the inequality produces a true statement, we will shade the region that contains the point. Otherwise, we will shade the opposite region. For simplicity, we will test the point (0,0).
2.5n+1.25p≥ 60
2.5( 0)+1.25( 0)? ≥ 60
0+0 ? ≥ 60
0 ≱ 60 *
Since (0,0) did not produce a true statement, we will shade the region that does not contain it.

The solution to this system of inequalities is where the three shadings overlap.


c To name one possible solution, we need any point from the overlapping area.

We will plot the point in the graph and name it.

As we see above, one possible solution is (40,100). In the context of the problem, it means that 40 notebooks and 100 pens were sold.