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McGraw Hill Glencoe Algebra 1, 2012

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McGraw Hill Glencoe Algebra 1, 2012 View details

6. Ratios and Proportions

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Exercise 62 Page 117

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

y=-15

Practice makes perfect

To solve an equation with a variable on both sides, we gather all of the variable terms on one side of the equation and all of the constant terms on the other side using the Properties of Equality.

9+y/5=6

LHS-9=RHS-9

y/5=-3

\MulEqn

y/5*5=-3*5

FracMultDenomToNumber

a/5* 5 = a

y=-3*5

(- a)b = - ab

y=-15

The solution to the equation is y=-15. We can check our solution by substituting it into the original equation.

9+y/5=6

y= -15

9+-15/5? =6

Calculate quotient

9+(-3)? =6

a+(- b)=a-b

9-3? =6

Subtract term

6=6

Since the left-hand side is equal to the right-hand side, our solution is correct.

Subchapter links

Check Your Understanding p.114

Practice and Problem Solving p.115-116

H.O.T. Problems p.116

Standardized Test Practice p.117

Spiral Review p.117

Skills Review p.117