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McGraw Hill Glencoe Algebra 1, 2012

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McGraw Hill Glencoe Algebra 1, 2012 View details

6. Ratios and Proportions

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Exercise 38 Page 115

You can solve for the variable by using the Cross Products Property.

- 3

Practice makes perfect

To solve the proportion, we will start by using the Cross Products Property. Remember that we will need to treat 9b-3 and 5b+5 as single quantities in the cross multiplication process.

9b-3/9=5b+5/3

Cross multiply

3(9b-3)=9(5b+5)

From here, we will continue solving for b by using the Distributive Property and the Properties of Equality.

3(9b-3)=9(5b+5)

Distribute 3

27b- 9 =9(5b+5)

Distribute 9

27b-9=45b+45

LHS-45b=RHS-45b

-18b-9=45

LHS+9=RHS+9

-18b=54

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Solve for b

.LHS /(-18).=.RHS /(-18).

-18b/-18=54/-18

- a/- b=a/b

18b/18=54/-18

MoveNegDenomToFrac

Put minus sign in front of fraction

18b/18=-54/18

Calculate quotient

b=- 3

Subchapter links

Check Your Understanding p.114

Practice and Problem Solving p.115-116

H.O.T. Problems p.116

Standardized Test Practice p.117

Spiral Review p.117

Skills Review p.117