McGraw Hill Glencoe Algebra 1, 2012
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McGraw Hill Glencoe Algebra 1, 2012 View details
6. Adding and Subtracting Rational Expressions
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Exercise 92 Page 719

Start by writing an expression for the total cost of the pizza.

Inequality: 172 .50+28.75x/20 ≤ 13
Number of Toppings: x≤ 3

Practice makes perfect
We are told that Ruben has $ 13 to order pizza. The pizza costs $ 7.50 and each topping costs $ 1.25. To find the number of toppings that he can order, we will first write an expression to define the total cost of the pizza. Let's say that x represents the number of toppings. Total Cost of the Pizza: 7.50 + 1.25x We also know that Ruben plans to tip 15 % of the total cost of the pizza. Tip: 15 %* ( 7.50 + 1.25x) Now that we have the total cost of the pizza with toppings and the cost of the tip, we can write the total amount of money that he needs to pay by adding them up.
7.50 + 1.25x + 15 % * (7.50 + 1.25x)
7.50 + 1.25x + 15/100* (7.50 + 1.25x)
7.50 + 1.25x + 3/20* (7.50 + 1.25x)
7.50 + 1.25x + 3 * (7.50 + 1.25x)/20
7.50 + 1.25x + 22.50+ 3.75x/20
150/20+ 25x/20+ 22.50+ 3.75x/20
172.50+28.75x/20
We are asked to write an inequality to represent the number of toppings that he can order. Since he has in total $ 13, we will write that the total cost must be less than or equal to 13. 172 .50+28.75x/20 ≤ 13 Let's solve this inequality for x.
172.50+28.75x/20 ≤ 13
â–Ľ
Solve for x
172 .50+28.75x ≤ 260
28.75x ≤ 87.50
x ≤ 3.043478...
x ≤ 3
Since the toppings cannot be a fraction, we can conclude that he can order a maximum of three toppings.