McGraw Hill Glencoe Algebra 1, 2012
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McGraw Hill Glencoe Algebra 1, 2012 View details
6. Adding and Subtracting Rational Expressions
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Exercise 65 Page 718

Practice makes perfect
a We are told that in a triathlon athletes swim 400 meters, bike 20 kilometers, and run 5 kilometers. An athlete bikes 12 times as fast as she swims, and runs 5 times as fast as she swims. We are given an expression that represents the total time that she needs to complete this triathlon.
400/x + 20 000/12x + 5 000/5xWe want to simplify the above expression. Notice that we have unlike denominators. To make the addition, we will rewrite each rational expression using a least common denominator (LCD). x:& x 12x: & 3 * 4 * x 5x:& 5 * x LCD: & 3 * 4 * 5 * x ⇒ 60x We found that the LCD is 60x. Now we can add the terms up by expanding the corresponding numbers to get the LCD. Let's do it!
400/x + 20 000/12x + 5 000/5x
400*60/60x + 20 000/12x + 5 000/5x
400*60/60x + 20 000 * 5/60x + 5 000/5x
400*60/60x + 20 000 * 5/60x + 5 000 * 12/60x
24 000/60x + 100 000/60x + 60 000/60x
184 000/60x
9200/3x
b We are given that an athlete swims 40 meters per minute. We want to find the total time that she needs to complete the triathlon. To do so, let's substitute x= 40 into the expression that we found in Part A.
9200/3x
9200/3* 40
9200/120
230/3
76 23
Since one minute is 60 seconds, 23 minute is equal to 40 seconds. Therefore, we can conclude that the athlete needs about 76 minutes and 40 seconds to complete the triathlon.