The is the sum of the and the combined of the two identical bases.
S=Ph+2B
Since the base of a cube is a with a side length
s, its area is equal to the of
s.
B=s2
The of the square base can be calculated as the of
4 and
s.
P=4s
Finally, the height of the cube is also equal to the side length
s. h=s
Now these values will be substituted into the and the resulting equation simplified.
SA=Ph+2B
SA=4s(s)+2s2
SA=4s2+2s2
SA=6s2