Glencoe Math: Course 3, Volume 2
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Glencoe Math: Course 3, Volume 2 View details
5. Similar Triangles and Indirect Measurement
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Exercise 6 Page 557

If two triangles are similar, then their corresponding angles are congruent and the lengths of their corresponding sides are proportional.

4.2ft

Practice makes perfect

We are given following diagram and want to find the height of the brace. Let's add some letters to our diagram to make it easier to reference the different parts of the triangles. We will first show that triangles ABC and ADE are similar. Once we know that the triangles are similar, we can use their proportional relationship to find the missing distance.

From the angle markers shown in the diagram, we can see that ∠ B is congruent to ∠ D and that ∠ C is congruent to ∠ E. ∠ B ≅ ∠ D ∠ C ≅ ∠ E

Since two angles of △ ABC are congruent to two angles of △ ADE, they are similar by the Angle-Angle (AA) Similarity rule. △ ABC ~ △ ADE Now, notice that AC corresponds to AE and BC corresponds to DE.

Remember that corresponding sides of similar figures will have proportional lengths. We know that AC= 7 feet, AE= 15 feet, and DE= 9 feet. We can use these lengths to write a proportion. AC/AE=BC/DE ⇔ 7/15=h/9 Let's solve this proportion using cross products.
7/15=h/9
7 * 9 = h * 15
Solve for h
63 = h * 15
63/15 = h * 15/15
4.2 = h * 15/15
4.2 = h * 15/15
4.2 = h * 1
4.2 = h
h = 4.2
The height of the brace is 4.2 feet.