Exercise 10 Page 658

We are given a square pyramid with a volume of 25 35 cubic meters and we know that the base edge is 4 meters. We want to find the height of this pyramid. Let's first recall the formula for the volume of a pyramid. V=1/3BhHere, B is the area of the base, and h is the height of the pyramid. Since the base is a square, the base's area B is a square of the base edge. Let's find this area! B = 4^2 = 16 The base's area is 16 square meters. Our pyramid has a volume of 25 35 cubic meters. Let's substitute this values into the formula for the volume of a pyramid. That way, we will get an equation for h. Then, let's solve this equation!

V=1/3Bh

SubstituteII

V= 25 35, B= 16

25 35=1/3( 16)h

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Simplify

WriteDec

Write as a decimal

3 * 25.6 = 16h

MultEqn

LHS * 3=RHS* 3

3 * 25.6 = 3* 1/3(16)h

Multiply

Multiply

76.8 = 3* 1/3(16)h

DenomMultFracToNumber

3 * a/3= a

76.8 = 1(16)h

IdPropMult

Identity Property of Multiplication

76.8 = 16h

DivEqn

.LHS /16.=.RHS /16.

76.8/16 = 16h/16

RearrangeEqn

Rearrange equation

16h/16=76.8/16

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Simplify left-hand side

MovePartNumRight

a* b/c=a/c* b

16/16h=76.8/16

QuotOne

a/a=1

1h=76.8/16

IdPropMult

Identity Property of Multiplication

h=76.8/16

CalcQuot

Calculate quotient

h = 4.8

The height is 4.8 meters.