Envision Math 2.0: Grade 8, Volume 1
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Envision Math 2.0: Grade 8, Volume 1 View details
4. Equations with No Solutions or Infinitely Many Solutions
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Exercise 6 Page 107

Assume that Todd and Agnes bought x pieces of fruit each.

Yes, see solution.

Practice makes perfect

We are told that Agnes and Todd are making dessert. Agnes buys apples and a jar of honey and Todd buys peaches and a carton of vanilla yogurt. Also, we are told that they both bought the same number of pieces of fruit. Let's say that each of them bought x fruits.

We are asked if it is possible for Todd and Agnes to pay the same amount of money for shopping. To determine that, let's first calculate how much Agnes paid for her shopping in terms of x. Agnes paid?$for shopping.

One apple costs $1 and a jar of honey costs $6. Agnes paid $6 for one honey jar. Also, since Agnes bought x apples, she paid x* $1 for them.

In total, Agnes paid 6+x* 1 dollars for her shopping. We can do similar calculations for Todd. He bought one carton of yogurt for $4 and x peaches for $ 1.25 each.

This means that Todd paid 4+x* 1.25 dollars for his shopping. Now, if Todd and Agnes paid the same amount of money for shopping, the following equation would be true. Todd paid & =Agnes paid & ⇕ 4+x* 1.25 & =6+x* 1 Let's try to solve this equation!
4+x* 1.25 =6+x* 1
4+1.25x =6+x
4+1.25x-x=6+x-x
4+0.25x=6
4-4+0.25x=6-4
0.25x=2
4*0.25x=4*2
x=8
We found that this equation has a solution, x=8. This means that a situation where Todd and Agnes paid the same amount of money for shopping is possible! It is when Todd buys 8 peaches and Agnes buys 8 apples.