Sign In
The y-intercept indicates the value of a function when x is equal to 0. In our case, the y-intercept is the value of a cost function when 0 tickets are bought.
The line is continuous, which means that x and y can have all real values. Is our data continuous?
y= 21x + 12.25
See solution.
No, see solution.
We are given the line that represents the cost of ordering concert tickets online. We want to write an equation for the line in slope-intercept form. In the equation x will represent the number of tickets and y will represent the total cost.
Substitute ( 0,12.25) & ( 1,33.25)
Subtract terms
a/1=a
We know that the y-intercept indicates the value of a function when x is equal to 0. That is why the y-intercept is also known as the initial value. In our case, the y-intercept is the value of a cost function when 0 tickets are bought, which is a processing fee equal to $12.25. Therefore, our y-intercept is 12.25. y= mx + 12.25 We know that the tickets cost $21 per ticket. In our case, the slope with denominator of 1 is a rate comparing change of costs when we increase the number of tickets by 1. We know that if we buy 1 more ticket, it will cost us $21 more. Therefore, the slope is 21. y= 21x + 12.25 We wrote the equation of the line without using the graph, only with the information about the ticket prices.
The line is continuous, so x and y can have all real values. In our case, x represents the number of tickets. This is not a continuous data, because we can only have whole number of tickets, like 3 or 4. We cannot have for example 2.5 or 14 tickets. Therefore, the line is not a good representation, we should draw separate points instead.
The graph is not a good representation also for another reason. The line starts at the point (0,12.25), which represents the situation in which we buy 0 tickets and pay $12.25 fee. This is unrealistic situation, because when we buy 0 tickets — there is no need to pay any fee. This point should not be included on the graph.