Core Connections Integrated II, 2015
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Core Connections Integrated II, 2015 View details
Chapter Closure

Exercise 153 Page 704

a We want to find the volume of the Smallville's baseball stadium. The top of the stadium is a hemisphere with a radius of 200 feet. Underneath it there is a cylinder with a base with the same radius and the height of 150 feet.

The volume of this stadium is the sum of volumes of the bottom cylinder and the top hemisphere.

Cylinder's Volume

The volume of a cylinder can be found using the following formula. V = π r^2 h Here, r is the radius of the cylinder's base and h is the cylinder's height. In our case, r = 200, feet and h = 150 feet, so let's substitute these values into our formula. Then, let's simplify the result to find the volume!
V = π r^2 h
V = π ( 200)^2( 150)
Simplify right-hand side
V = π (40 000)(150)
V = 6 000 000 π
The volume of the cylinder is 6 000 000 π cubic feet.

Hemisphere

The volume of a sphere with a radius r equals 43 π r^3. Since we have a hemisphere, its volume is half the volume of a sphere with the same radius. For this reason, we have the following formula for the volume of a hemisphere with a radius r. V = 2/3 π r^3 Let's substitute 200 for r in the above formula and simplify.
V = 2/3 π r^3
V = 2/3 π ( 200)^3
Simplify right-hand side
V = 2/3 π (8 000 000)
V = 2/3 (8 000 000)π
V = 2 * 8 000 000/3 π
V = 16 000 000/3 π
The volume of our hemisphere is about 16 000 0003 π cubic feet.

Stadium's Volume

The stadium's volume is a sum of volumes of the bottom cylinder and the top hemisphere. Let's find it! 6 000 000 π + 16 000 000/3 π ≈ 35 600 000 The stadium's volume is about 35 600 000 cubic feet.

b We want to find the surface area of the outside of the Smallville's baseball stadium. The top of the stadium is a hemisphere with a radius of 200 feet. Underneath it there is a cylinder with a base with the same radius and the height of 150 feet.

Since we do not include the base of the cylinder, the surface area we want to find is the sum of the lateral surface area of a cylinder and the curved surface area of the hemisphere.

Cylinder's Lateral Area

The cylinder's lateral area can be found using the following formula. L = 2π r h Here, r is the radius of the cylinder's base and h is the cylinder's height. In our case, r = 200, feet and h = 150 feet, so let's substitute these values into our formula. Then, let's simplify the result to find the volume!
L = 2π r h
L = 2 π ( 200)( 150)
L = 60 000 π
The lateral area of the cylinder is about 60 000 π square feet.

Curved Area of a Hemisphere

The surface area of a sphere with a radius r equals 4 π r^2. Since we have a hemisphere, its curved area is half the surface area of a sphere with the same radius. For this reason, we have the following formula for the curved area of a hemisphere with a radius r. V = 2 π r^2 Let's substitute 200 for r in the above formula and simplify.
V = 2 π r^2
V = 2 π ( 200)^2
Simplify right-hand side
V = 2 π (40 000)
V = 80 000 π
The curved area of the hemisphere is about 80 000 π square feet.

Stadium's Outside Area

The stadium's outside area is a sum of volumes of the bottom cylinder and the top hemisphere. Let's find it! 60 000 π + 80 000 π ≈ 440 000 The stadium's outside area is about 440 000 square feet.