Core Connections Geometry, 2013
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Core Connections Geometry, 2013 View details
3. Section 5.3
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Exercise 105 Page 319

Practice makes perfect
a The only way to achieve a sum of 4 is if you get a 2 on both spinners. To identify this probability we have to determine how large an area these sectors occupy of their respective circles.

Spinner #1

From the diagram, we see that the sector with a 2 has a right angle. Therefore, it occupies 90^(∘)360^(∘)= 14 of the circle and the second sector occupies the remaining part, 34.

Spinner #2

In the second spinner each field occupies a third of the circle. Therefore, the probability of getting a 2 on the second spinner is 120^(∘)360^(∘)= 13. We get the following diagram.

Tree Diagram

We can illustrate getting two 2's with a tree diagram.

To calculate the probability of getting 2 twice — in other words a sum of 4 — we have to multiply the individual probabilities of these events. P(sum is 4)=1/4* 1/3=1/12

b To obtain a sum of 8, we have two paths to consider. Either we can get a 4 on both spinners, or, we can get a 2 on the first spinner and a 6 on the second spinner. Let's mark these paths in our tree diagram from Part A.
Like in Part A, we can calculate P(2,6) and P(4,4) by multiplying the individual probabilities. P(2,6)=1/4* 1/3=1/12 [0.8em] P(4,4)=3/4* 1/3=3/12 By adding these individual probabilities we get the total probability of getting a sum of 8.
P(sum is 8)=P(2,6)+P(4,4)
P(sum is 8)= 1/12+ 3/12
P(sum is 8)=4/12
P(sum is 8)=1/3
The probability of getting a sum of 8 is 13.