c The slopes of perpendicular lines have a product of - 1.
A
a y=- 3/5x+3
B
b Area= 7.5
Perimeter≈ 13.83
C
c y=5/3x+3
Practice makes perfect
a To find the equation of AB, we have to determine it's slope, m, and y-intercept b.
y=mx+ b
Examining the diagram, we can identify where AB intercepts the y-axis.
The line intercepts the y-axis at (0,3) which means b= 3. To find the slope, we have to measure the vertical and horizontal distance between two points on the graph. The only points that lie on coordinates we can identify, are the x- and y-intercept.
Traveling from the y-intercept to the x-intercept requires that we move 5 steps horizontally in the positive direction and 3 steps vertically in the negative direction. With this, we can find the slope.
rise/run=-3/5 ⇔ m= - 3/5
Now that we have the slope and the y-intercept, we can form our final equation.
y= mx+b
y= - 3/5x+3
The area of the triangle is 7.5units^2. To find the perimeter we have to add its three sides. Since we do not know the length of the hypotenuse, we must calculate it. We can do this by using the Distance Formula.
When we know the hypotenuse, we can finally calculate the perimeter by adding all of the sides.
Perimeter: 5+3+sqrt(34)≈ 13.83 units
c To write the equation of a line perpendicular to AB, we first need to determine its slope. Two lines are perpendicular when their slopes are opposite reciprocals. This means that the product of a given slope and the slope of a line perpendicular to it will be -1.
m_1*m_2=-1From Part A, we know the slope of AB. By substituting the slope of AB into the equation, we can solve for the slope of the perpendicular line, m_2.
Any line perpendicular to the given equation will have a slope of 53. Since we know the line intercepts the y-axis at point A, we know that b=3. With this, we can write the equation of the line through A that is perpendicular to AB as y= 53x+3.
