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Note that the same song cannot be played twice. Therefore, we have to exclude all combinations of the same song being played by shading those fields.
Also, the order she hears the song does not matter. For example, the combination I Love My Mama,
Don't Call Me Mama
and Don't Call Me Mama,
I Love My Mama
is regarded as the same combination. Therefore, we have to shade a few more combinations to avoid double counting.
In total there are 10 combinations. Let's list all of the them. (a,b), (a,c), (a,d), (a,e), (b,c), (b,d), (b,e), (c,d), (c,e), (d,e)
There are a total of 3 combinations where both songs contain the word "Mama". From Part A, we know that there is a total of 10 combinations. With this, we can determine the probability of Renae listening to two songs with the name Mama in the title. P(two songs with "Mama")=3/10
There are a total of 9 combinations where at least one song contain the word "Mama". From Part A we know that there is a total of 10 combinations. With this, we can determine the probability of Renae listening to at least one song with the word "Mama". P(two songs with "Mama")=9/10
Mama,this excludes all combinations of songs where one song does not contain this word. If only one song has to contain the word, it opens up for more combinations which means the number of favorable outcomes is greater. For this reason, it makes sense that the probability is higher.