2. Section 1.2
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m_2= -2/5
a(- b)=- a * b
LHS * 5=RHS* 5
LHS * (-1)=RHS* (-1)
.LHS /2.=.RHS /2.
|c|c|c| Line & Slope & y-intercept [-0.8em] y= 3/2x+ 5& 3/2 & 5 [0.8em] As already explained, if two lines are parallel, they have to have the same slope but different y-intercepts. Therefore, we know that the parallel line must have a slope of 32. |c|c|c| Parallel Line & Slope & y-intercept [-0.8em] y= 3/2x+ b& 3/2 & b [0.8em] Like in Part A, we see that the given point has an x-coordinate of 0. This means the points y-coordinate describes the line's y-intercept. With this information, we can write the line's equation. y=3/2x+7 If we plot both lines, we see that they are parallel.