Exercise 115 Page 427

We want to solve the given equation for x. 5.2+x=10.95 We can start by using the Subtraction Property of Equality to isolate x on the left-hand side of the equation. Let's subtract 5.2 from both sides of the equation.

5.2+x=10.95

SubEqn

LHS-5.2=RHS-5.2

5.2+x-5.2=10.95-5.2

CommutativePropAdd

Commutative Property of Addition

x+5.2-5.2=10.95-5.2

SubTerm

Subtract term

x=5.75

We want to solve the given equation for x. 2x-3.25=7.15 We can start by using the Addition Property of Equality to isolate x on the left-hand side of the equation. Let's add 3.25 to both sides of the equation!

2x-3.25=7.15

AddEqn

LHS+3.25=RHS+3.25

2x-3.25+3.25=7.15+3.25

AddTerms

Add terms

2x=10.4

Next, we can use the Division Property of Equality to eliminate the coefficient of 2x. Let's divide both sides of the equation by 2!

2x=10.4

DivEqn

.LHS /2.=.RHS /2.

2x/2=10.4/2

MovePartNumRight

a* b/c=a/c* b

2/2x=10.4/2

▼

Simplify left-hand side

QuotOne

a/a=1

1x=10.4/2

IdPropMult

Identity Property of Multiplication

x=10.4/2

CalcQuot

Calculate quotient

x=5.2

We want to solve the given equation for x. x/16=3/8 Notice that 16 is a multiple of 8. This means that we can find the value of x by rewriting 38 with the same denominator as the fraction on the left-hand side, 16.

x/16=3/8

ExpandFrac

a/b=a * 2/b * 2

x/16=3* 2/8* 2

Multiply

Multiply

x/16=6/16

MultEqn

LHS * 16=RHS* 16

x/16* 16=6/16* 16

FracMultDenomToNumber

a/16* 16 = a

x=6