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any number?
(any number)* x^((whole number)) Let's check if the terms follow the description of a polynomial. ( any number)* x^(( whole number)) ↓ y= 3x^2+ 2x^2+ 1x^1 As we can see, the equation is a polynomial.
(a-b)^2=a^2-2ab+b^2
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( any number)* x^(whole number) ↓ y= 1x^2+ 2^x Therefore, this function is not a polynomial.
( any number)* x^(whole number) ↓ y= 3x^1- 1x^0 This function is a polynomial.
( any number)* x^(whole number) ↓ y= 1x^(-2)+ 1x^(-1)+ 1/2x^0 As we can see, the function is not a polynomial.
( any number)* x^(whole number) ↓ y= 1/2x^1+ 1/3x^0 The function is a polynomial.
( any number)* x^(whole number) ↓ y= 1x^1 The function is a polynomial.
( any number)* x^(whole number) ↓ y= - 7x^0 The function is a polynomial.