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We are given that the x-intercepts occur at (2,0) and (7,0). Let's plot these points.
The axis of symmetry is halfway between x-intercepts (x_1,0) and (x_2,0). Since we know that x_1=2 and x_2=7, the axis of symmetry of our parabola is halfway between (2,0) and (7,0). x=x_1+ x_2/2 ⇒ x=2+ 7/2=9/2=4.5 We found that the axis of symmetry is the vertical line x=4.5.
We are given that the y-intercept is (0,- 8). Let's plot this point and its reflection across the axis of symmetry.
Finally, we will draw the parabola through the points we found.
Let's go through these steps one at a time.
When a quadratic function has only one x-intercept, it means that this point is also a vertex of the parabola. Since our function has the x-intercept at (- 1,0), we know that the parabola has the vertex at the point (- 1,0).
The axis of symmetry is a vertical line that divides the graph into two mirror images. Since the axis of symmetry of the parabola intersects vertex, we know that the equation of the axis is equal to the x-coordinate of the vertex. In our case it is x=- 1.
We are given that the y-intercept is (0,3). Let's plot this point and its reflection across the axis of symmetry.
We can now draw the graph of the function. Let's connect the three points with a smooth curve.
Let's go through these steps one at a time.
y=a(x+b)(x+c) In this form, where a ≠0, the x-intercepts are (- b,0) and (- c,0). Let's consider the factored form of our function. y=(x+5)(x-1) ⇕ y= 1(x+ 5)(x+( - 1)) We can see that a= 1, b= 5, and c= - 1. Therefore, the x-intercepts occur at ( - 5,0) and ( 1,0).
The axis of symmetry is halfway between the x-intercepts (- b,0) and (- c,0). Since we know that - b=- 5 and - c=1, the axis of symmetry of our parabola is halfway between (- 5,0) and (1,0). x=- b+( - c)/2 ⇒ x=- 5+ 1/2=- 4/2=- 2 We found that the axis of symmetry is the vertical line x=- 2.
Finally, we will draw the parabola through the vertex and the x-intercepts.