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Use the Zero Product Property
(I): LHS+4=RHS+4
(II): LHS-1=RHS-1
(II): .LHS /2.=.RHS /2.
We found that x=4 or x=- 12.
To factor a trinomial with a leading coefficient of 1, think of the process as multiplying two binomials in reverse. Let's start by taking a look at the constant term.
x^2+5x+6=0
| Factor Constants | Product of Constants |
|---|---|
| 1 and 6 | 6 |
| -1 and -6 | 6 |
| 2 and 3 | 6 |
| -2 and -3 | 6 |
Next, let's consider the coefficient of the linear term. x^2+5x+6=0 For this term, we need the sum of the factors that produced the constant term to equal the coefficient of the linear term, 5.
| Factors | Sum of Factors |
|---|---|
| 1 and 6 | 7 |
| -1 and -6 | -7 |
| 2 and 3 | 5 |
| - 2 and - 3 | - 5 |
We found the factors whose product is 6 and whose sum is 5. x^2+5x+6=0 ⇔ (x+2)(x+3)=0
Since the equation is already written in factored form, we can now use the Zero Product Property.
Use the Zero Product Property
(I): LHS-2=RHS-2
(II): LHS-3=RHS-3
We found that x=- 2 or x=- 3.
Use the Zero Product Property
(II): LHS+5=RHS+5
(II): .LHS /2.=.RHS /2.
We found that x=0 or x= 52.
The GCF of an expression is a common factor of the terms in the expression. It is the common factor with the greatest coefficient and the greatest exponent. In this case, the GCF is x.
Now, the equation is written in a factored form.
Since the equation is already written in factored form, we can now use the Zero Product Property.
Use the Zero Product Property
(II): LHS-4=RHS-4
We found that x=0 or x=- 4.