Core Connections Algebra 1, 2013
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Core Connections Algebra 1, 2013 View details
2. Section 2.2
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Exercise 66 Page 71

Practice makes perfect
a To find the cube root of 1, we can consider the value that, when multiplied by itself 3 times, equals 1.

sqrt(1)=x ⇔ 1=x^3 To help us find this value of x, we can list the cubes of the integers from 0 to 5.

x x^3
0 0
1 1
2 8
3 27
4 64
5 125

From the table, we can see that 1^3=1. Therefore, sqrt(1)=1.

b Similar to Part A, we can write the given expression with an exponent.

sqrt(0)=x ⇔ 0=x^3 From the table in Part A, we can see that 0^3=0. Hence, sqrt(0)=0.

c Similar to previous parts, we can rewrite the given expression as an equation.

sqrt(2^3)=x ⇔ 2^3=x^3 We can see that to get true statement x must equal 2. Therefore sqrt(2^3)=2

d One last time, let's rewrite the given expression.

sqrt(7^3)=x ⇔ 7^3=x^3 Think just as in the previous part, x must equal 7 to get a true statement. Hence, sqrt(7^3)=7.