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| | 9 Theory slides |
| | 9 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
By applying rigid motions, investigate whether the given pair of triangles are congruent or not.
When a rigid motion is applied to a polygon, the resulting image can be seen as the polygon formed by the image of each part of the original polygon under the same rigid motion.
Consider two figures. One figure is the image of the other under a transformation. The pairs formed by a part of the preimage — a side, angle, or vertex — and the image of that part are called corresponding parts. For example, in the following applet, A and P are corresponding vertices.
| Congruent or Similar? | Relationship |
|---|---|
| Congruent | The corresponding sides and angles of the figures are congruent. |
| Similar | The corresponding sides of the figures are proportional.
The corresponding angles of the figures are also congruent. |
When two triangles are congruent, it seems natural to think that the corresponding parts are congruent as well. What about the same concept when the statement is reversed? That is to say, if the corresponding parts of two triangles are congruent, are the triangles congruent? The following claim answers this question.
Two triangles are congruent if and only if their corresponding sides and angles are congruent.
Using the triangles shown, this claim can be written algebraically as follows.
△ ABC ≅ △ DEF ⇕ AB≅DE BC≅EF AC≅DF and ∠A≅∠D ∠B≅∠E ∠C≅∠F
By definition of congruent figures, if the triangles are congruent there is a rigid motion or sequence of rigid motions that maps △ ABC onto △ DEF.
Because rigid motions preserve side lengths, AB and its image have the same length, that is, AB=DE. Therefore, AB≅DE. Similarly for the other two side lengths. BC≅EF and AC≅DF Furthermore, rigid motions preserve angle measures. Then, ∠ A and its image have the same measure, that is, m∠ A = m∠ D. Therefore, ∠ A ≅ ∠ D. Similarly for the remaining angles. ∠ B ≅ ∠ E and ∠ C ≅ ∠ F That way, it has been shown that if two triangles are congruent, then their corresponding sides and angles are congruent.
To begin, mark the congruent parts on the given diagram.
The primary purpose is finding a rigid motion or sequence of rigid motions that maps one triangle onto the other. This can be done in several ways, here it is shown one of them.
As seen, △ A'B'C' did not match △ DEF. Therefore, a second rigid motion is needed.
As before, the image did not match △ DEF. Thus, a third rigid motion is required.
This time the image matched △ DEF.
Consequently, through applying different rigid motions, △ ABC was mapped onto △ DEF. This implies that △ ABC and △ DEF are congruent. Then, the proof is complete.
The local chess team in Jordan's town has designed a fancy new logo.
What is the sum of the perimeters of both triangles?
Then, find and label the side lengths and angle measures of each triangle.
As seen, both triangles have the same side lengths and angle measures. That is, all their corresponding sides and angles are congruent. Therefore, the two triangles are congruent. Jordan was correct!
The new logo is made of two congruent triangles.
Because the triangles are congruent, they have the same perimeter. Then, it is enough to find the perimeter of only one of them and then multiply it by 2. Remember, the perimeter is the sum of the side lengths. P_1 &= 1.5+3+3.4 P_1 &= 7.9 Finally, the sum of the perimeters of both triangles is twice P_1. That can be expressed as 2* P_1 = 2*7.9 = 15.8.
To show that two triangles are not congruent, it is enough to find only one side or angle of one of the triangles that is not congruent to any side or angle of the second triangle.
Mark, Magdalena, and Kevin each bought a notebook with a triangle design on the cover.
Are there any pairs of congruent triangles? If so, which ones are congruent?
The triangle in Mark's notebook is not congruent to any of the other triangles.
Now, moving on to Madaelena's notebeook. Notice that the triangle has the same angle measures as the triangle in Kevin's notebook.
Before concluding that these two triangles are congruent, remember, all the corresponding parts have to be congruent. Therefore, the sides opposite to the 80^(∘) angle of each triangle should be congruent. Well, that is not the case.
It was a close call, but the triangle in Magdalena's notebook is not congruent to the triangle in Kevin's notebook. As a result, none of the triangles are congruent to the others.
The following figure is made of 5 triangles.
How many pairs of congruent triangles are there?
By applying the concept of reading the marks to check for congruency, it can be said that BF is not congruent to any side of △ AFG. Consequently, △ AFG is not congruent to △ ABF. By the same reasoning, △ AFG is not congruent to △ BFD either. △ AFG ≆ △ ABF △ AFG ≆ △ BFD Next, compare △ AFG to △ DEF.
Since ∠ G and ∠ DFE have both a measure of 50^(∘), they are congruent angles. Furthermore, the rest of the corresponding parts of these two triangles are congruent. ccc AF ≅ DE & & ∠ GAF ≅ ∠ FDE FG ≅ EF & and & ∠ AFG ≅ ∠ DEF AG ≅ DF & & ∠ FGA ≅ ∠ EFD Consequently, △ AFG and △ DEF are congruent. Similarly, it can be checked that △ AFG is also congruent to △ BDC. By the Transitive Property of Congruence, a third pair of congruent triangles can be obtained.
Next, compare △ ABF to △ DFB. Since ∠ AFB and ∠ DBF have the same measure, they are congruent. Additionally, BF is a common side for both triangles and, by the Reflexive Property of Congruence, BF≅ BF. BF≅ BF and ∠ AFB ≅ ∠ DBF In addition, the rest of corresponding parts of these two triangles are congruent. ccc AB ≅ DF && ∠ FAB ≅ ∠ BDF BF ≅ FB &and& ∠ ABF ≅ ∠ DFB AF ≅ DB && ∠ BFA ≅ ∠ FBD Consequently, △ ABF and △ DFB are congruent. So far, there are four pairs of congruent triangles. △ ABF &≅ △ DFB △ AFG &≅ △ DEF △ AFG &≅ △ BDC △ DEF &≅ △ BDC Taking into account the Transitive Property of Congruence, and the fact that △ ABF is not congruent to △ AFG, it can be said that there are no more pairs of congruent triangles.
As with polygons, when it comes to writing a triangle congruence statement, the order in which the vertices are written is critical. Naming them in an incorrect order leads to erroneous conclusions. Consider, for example, the following congruent triangles.
Although the triangles are congruent, the congruence statement △ ABC ≅ △ MQT is incorrect. Why? Because it would lead to the following conclusions about the sides and angles.
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Two polygons are congruent if and only if their corresponding sides and angles are congruent. |
Find the values of x and y if STU ≅ PMN.
In congruent figures, corresponding angles are congruent as are corresponding sides. From the congruence statement, we see that ∠ U and ∠ N are corresponding. △STU ≅ △ PMN [-1em] S→ P, T → M, U→ N We do not know m∠ N. But since we know the measures of the other two angles in △ PMN, we can find it by using the Interior Angles Theorem. 140^(∘)+m∠ N+24^(∘)=180^(∘) ⇓ m∠ N=16^(∘) Now we have the measures of all of the angles in △ MNP. Using the congruence statement, we can equate m∠ N with m ∠ U and the length of NP with the length of SU. This means we can write the following system of equations. 2x-50=16 2x-y=14 Let's solve this system by using the Substitution Method.
The value of x is 33 and the value of y is 52.
Dylan is on a quest in a role-playing game. He is given this piece of paper.
To advance to the next stage in the quest, he must find the values of x and y.
Let's make a diagram to help us visualize the given information. Remember that the order in which the vertices appear in the congruence statement matters. It tells us which vertices that are corresponding.
Notice that we know the measures of two angles in △ LMN. This means we can use the Interior Angles Theorem to find the measure of its third angle, ∠ N. 40^(∘)+90^(∘)+m∠ N=180^(∘) Let's solve this equation.
We can add this piece of information to our diagram.
Since we know that ∠ P≅ ∠ L and ∠ R≅ ∠ N we can create the following system of equations. 17x-y=40 2x+4y=50 Let's solve this system using the Elimination Method.
Having solved the system of equations for x, we can substitute this value into the first equation to solve for y.
We have found that x is 3 and y equals 11.