Big Ideas Math: Modeling Real Life, Grade 8
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Exercise 11 Page 192

The point-slope form is y-y_1=m(x-x_1).

y-3=1/4(x-4)

Equations in point-slope form follow a specific format. y- y_1= m(x- x_1) In this form, m is the slope of the line and ( x_1, y_1) is a point on the line. Here we are given that the line passes through two known points. (- 4,1) and (4,3) To determine the slope of the line, we use the Slope Formula.
m=y_2-y_1/x_2-x_1
m=3- 1/4-( - 4)
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Simplify right-hand side
m=2/4-(- 4)
m=2/4+4
m=2/8
m=1/4
Now that we know the slope of the line is 14, we can write the equation of the line in point-slope form. We can use either of the given points as (x_1,y_1) in our equation. Let's use ( 4, 3).
y-y_1=m(x-x_1)
y- 3= 1/4(x- 4)
Please note that any point on the line can be used to form a point-slope equation. Therefore, our equation is only one of infinitely many possible equations!

Extra

Slope-intercept form
Since any point on the line could be used to form a point-slope equation, there are infinitely many possible equations. To write a unique equation for this line, we can rewrite it in slope-intercept form.
y-3=1/4(x-4)
y-3+3=1/4(x-4)+3
y=1/4(x-4)+3
y=1/4x-1/4(4)+3
y=1/4x-1+3
y=1/4x+2