Big Ideas Math: Modeling Real Life, Grade 8
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Big Ideas Math: Modeling Real Life, Grade 8 View details
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Exercise 13 Page 134

What types of angle pairs do you know in case of two parallel lines cut by a transversal?

See solution.

Let's take a look at the given diagram of two parallel lines cut by a transversal.

We are asked to describe two ways in which we can find the measure of ∠ 5. Before we do that, let's review the definitions of different types of angle pairs.

Pairs of Angles
Type Definition
Supplementary Angles Together, they form a straight line and their measures add up to 180^(∘).
Vertical Angles They lie on the opposite sides of the point of intersection of two lines.
Corresponding Angles They lie in corresponding positions on the same side of the transversal.
Alternate Interior Angles They lie between the two lines on opposite sides of the transversal.
Alternate Exterior Angles They lie outside the two lines on opposite sides of the transversal.

Now let's describe the different ways to find the measure of ∠ 5.

First Way

First, we can see that angle 65^(∘) and ∠ 1 together form a straight line. Therefore these angles are supplementary angles.

The measures of supplementary angles add up to 180^(∘). We can use this fact to find the measure of ∠ 1. ∠ 1+ 65^(∘)=180^(∘) ⇕ ∠ 1 = 115^(∘) Next, let's notice that ∠ 1 and ∠ 5 are corresponding angles because they lie in corresponding positions on the same side of the transversal. This means that they have the same measures. ∠ 5 = ∠ 1 = 115^(∘) The measure of ∠ 5 is 115^(∘).

Second Way

Let's think of another way of finding the measure of ∠ 5. First, we can see that angle 65^(∘) and ∠ 6 are corresponding angles.

When a transversal intersects parallel lines, corresponding angles are congruent. This means that ∠ 6=65^(∘). Next, let's notice that ∠ 5 and ∠ 6 form a straight angle. This means that they are supplementary and their measures add up to 180^(∘).
∠ 5+∠ 6 = 180^(∘)
∠ 5 + 65^(∘)=180^(∘)
∠ 5= 115^(∘)
Notice that these are only two ways of finding the measure of ∠ 5 and that there are more possible solutions.