Big Ideas Math: Modeling Real Life, Grade 8
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Big Ideas Math: Modeling Real Life, Grade 8 View details
1. Volumes of Cylinders
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Exercise 7 Page 431

The Elimination Method can be used to solve a system of linear equations if either of the variable terms would cancel out the corresponding variable term in the other equation when added together.

C

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To solve a system of linear equations using the Elimination Method, one of the variable terms needs to be eliminated when one equation is added to or subtracted from the other. This means that either the x- or the y-terms must cancel each other out. 3 x+4 y=-10 & (I) 2 x-4 y=0 & (II) We can see that the y-terms will eliminate each other if we add Equation (I) to Equation (II).
3x+4y=-10 2x-4y=0
3x+4y=-10 2x-4y+( 3x+4y)=0+( -10)
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(II):Solve for x
3x+4y=-10 2x-4y+3x+4y=0+(-10)
3x+4y=-10 2x-4y+3x+4y=0-10
3x+4y=-10 5x=-10
3x+4y=-10 5x/5=-10/5
3x+4y=-10 5x/5=-10/5
3x+4y=-10 5x/5=-5(2)/5
3x+4y=-10 5x/5=-5(2)/5
3x+4y=-10 x=-2
Now we can solve for y by substituting the value of x into either equation and simplifying.
3x+4y=-10 x=-2
3( -2)+4y=-10 x=-2
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(I):Solve for y
-3 * 2+4y=-10 x=-2
-6+4y=-10 x=-2
-6+4y+6=-10+6 x=-2
4y=-4 x=-2
4y/4=-4/4 x=-2
4y/4=-4/4 x=-2
4y/4=-4(1)/4 x=-2
4y/4=-4(1)/4 x=-2
y=-1 x=-2
The solution, or point of intersection, of the system of equations is (-2,-1). Therefore, the correct option is C.