Big Ideas Math: Modeling Real Life, Grade 8
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Big Ideas Math: Modeling Real Life, Grade 8 View details
3. Solving Equations with Variables on Both Sides
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Exercise 19 Page 21

Practice makes perfect
We are jogging at a speed of 6 miles per hour with our friend, who is biking at 8 miles per hour. We want to find if our friend passes us before the end of the trail. To do so, consider that distance is the product of the speed and time. The distance traveled by our friend will be the sum of our distance traveled and 4 miles. 8 x=4+6 xHere, x represents the time after which our friend passes in front of us. Now, we can use inverse operations to isolate the variable on one side of the equation.
8x=4+6x
8x-6x=4+6x-6x
2x=4
2x/2=4/2
2x/2=4/2
x=4/2
x=2
After 2 hours our friend passes in front of us. To know if hour friend passes us before the end of the trail, we will calculate the distance traveled by our friend. Let's substitute x= 2 into the expression for the distance traveled by our friend.
8x
8* 2
16
Our friend biked 16 miles in 2 hours. Since the trail is only 10 miles long, our friend will pass us after the end of trail. This is because 16 is greater than 10.
Now, we have five-mile head start and run at 7 miles per hour with our friend, who is biking at 17 miles per hour. 17 x=5+7 xHere, x represents the time after which our friend passes in front of us. We can use inverse operations to isolate the variable on one side of the equation.
17x=5+7x
17x-7x=5+7x-7x
10x=5
10x/10=5/10
10x/10=5/10
x=5/10
x=1/2
x=0.5
After 0.5 hours our friend passes in front of us. To know if hour friend passes us before the end of the trail, we will calculate the distance traveled by our friend. Let's substitute x= 0.5 into the expression for the distance traveled by our friend.
17x
17* 0.5
8.5
Since the trail is 10 miles long, our friend will pass us before the end of trail. This is because 8.5 is less than 10.