We want to construct a trapezoid with base angles of 40^(∘). We can begin by drawing a segment of any length, and measuring the angles 40^(∘) and 40^(∘) with a protractor. We can denote the angle measures as m∠ A= 40 and m∠ B= 40.
Now, we can recall that a trapezoid has at least one pair of parallel sides. In this case, we can the third vertex, denoted with C, on one of the rays and use straightedge to draw a side parallel to the segment AB. Let's do it!
Notice that the fourth vertex of our trapezoid, denoted with D, is the point of intersection of the rays starting at A and C. Finally, we can draw our trapezoid.
Note that our graph is one of many possible solutions.
