Big Ideas Math Integrated I, 2016
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Big Ideas Math Integrated I, 2016 View details
1. Measures of Center and Variation
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Exercise 5 Page 336

Practice makes perfect
a We want to find mean, median, and mode of the given data set.
3 , 5 , 1 , 5 , 1 , 1 , 2 , 3 , 15 Let's find these measures of center one at a time.

Mean

The mean x of a data set is calculated by finding the sum of all of the values in the set and then dividing by the number of values in the set. In this case, there are 9 values in the set.
Mean=Sum of values/Number of values
x=3+ 5+ 1+ 5+ 1+ 1+ 2+ 3+ 15/9
â–Ľ
Evaluate right-hand side
x=36/9
x=4
The mean of the set is 4.

Median

When the data are arranged in numerical order, the median is the middle value — or the mean of the two middle values. Let's arrange the given values and find the median. 1 , 1 , 1 , 2 , 3 , 3 , 5 , 5 , 15 The median of this set is 3.

Mode

The mode is the value or values that appear most often in a set of data. Let's find the mode of the given values. 3 , 5 , 1 , 5 , 1 , 1 , 2 , 3 , 15 The value that appears most often is 1, so this is our mode.

b The mode 1 is the smallest number in the list. Therefore, it is not the measure that best represents the data.

ccc Mode & Median & Mean * & ? & ? In the given list, 15 is a value that is way bigger than the rest. This value can be considered an outlier. Outliers affect the mean but not the median. Therefore, since it is pulled up by the outlier, the mean is not the measure that best represents the data. This means that the median is the measure that best represents the data. ccc Mode & Median & Mean * & âś“ & *