Big Ideas Math Integrated I, 2016
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Big Ideas Math Integrated I, 2016 View details
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Exercise 6 Page 370

The range is the difference between the greatest and least value. The standard deviation measures how much the data elements differ from the mean.

Ranges: 110, 150
Standard Deviations: Approximately 39.4 and 48.1
Comparison: See solution.

Practice makes perfect

We want to find the range and standard deviation of each of the given data sets.

Store A Store B
$140 $180 $225 $310
$200 $250 $260 $190
$150 $190 $190 $285
$250 $160 $160 $240

Range

The range is the difference between the greatest and least values in a set of data. Now, we can rewrite each data set as an ordered list of numerical values and find their range.

Store A

Let's start with the tablet prices from store A. $140, $150, $160, $180, $190, $200, $250, $250 For this data set, the greatest value is 250 and the least value is 140. Range: 250- 140=110

Store B

Now, we can do the same for the prices from store B. $160, $190, $190, $225, $240, $260, $285, $310 For this data set, the greatest value is 310 and the least value is 160. Range: 310- 160=150

Standard Deviation

The standard deviation of a set of data is the average amount by which each individual value deviates or differs from the mean. Standard Deviation sqrt((x_1-μ )^2 +(x_2-μ )^2 +... +(x_n-μ )^2/n) In the above formula, x_1, ... ,x_n are the values of the set of data, μ is the mean, and n is the number of values.

Store A

For this data set, we can calculate the sum of the values. 140+150+160+180+ 190+200+250+250 = 1520 The mean is the sum of the values 1520 divided by the number of values 8. μ= 1520 8=190 Let's use this value and apply the formula to each value in the set.

x_n x_n-μ (x_n-μ)^2
140 140-190=-50 (-50)^2= 2500
150 150-190=-40 (-40)^2= 1600
160 160-190=-30 (-30)^2= 900
180 180-190=-10 (-10)^2= 100
190 190-190=0 0^2= 0
200 200-190=10 10^2= 100
250 250-190=60 60^2= 3600
250 250-190=60 60^2= 3600
Sum of Values = 12400

Finally, we need to divide by 8 and then calculate the square root. Standard Deviation: sqrt(12400/8)≈ 39.4

Store B

For this data set, we can calculate the sum of the values. 160+190+190+225+ 240+260+285+310 = 1860 The mean is the sum of the values 1860 divided by the number of values 8. μ= 1860 8=232.5 Let's use this value and apply the formula to each value in the set.

x_n x_n-μ (x_n-μ)^2
160 160-232.5=-72.5 (-72.5)^2= 5256.25
190 190-232.5=-42.5 (-42.5)^2=1806.25
190 190-232.5=-42.5 (-42.5)^2=1806.25
225 225-232.5=-7.5 (-7.5)^2= 56.25
240 240-232.5=7.5 7.5^2= 56.25
260 260-232.5=27.5 27.5^2= 756.25
285 285-232.5=52.5 52.5^2= 2756.25
310 310-232.5=77.5 77.5^2= 6006.25
Sum of Values = 18500

Finally, we need to divide by 8 and then calculate the square root. Standard Deviation: sqrt(18500/8)≈ 48.1

Comparison

The range of the tablet prices for Store A is 110, and the range of the prices for Store B is 150. So, the prices are more spread out for Store B. The standard deviation for Store A is about 39.4, and the standard deviation for Store B is about 48.1. Therefore, the typical price for Store A differs by 39.4 from the mean, while the typical price for Store B differs by 48.1.