Cumulative Asssessment
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Multiply Inequality 1 by - 3.
6x-3y<- 12
l Inequality 1 y-2x≤ 4 Inequality 2 6x-3y -12 We are asked to fill with <, ≤, >, or ≥, so that the given system has no solution. Therefore, the solutions of each inequality should be completely different. Notice that the coefficients in both inequalities are proportional. Let's multiply Inequality 1 by - 3. l Inequality 1 y-2x≤ 4 Inequality 2 6x-3y -12 ⇓ l Inequality 1 6x-3y≥ - 12 Inequality 2 6x-3y -12 Notice that the both inequalities looks almost the same. Since we want the system to have no solutions, the signs should be opposite. Therefore, we should fill with <.