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Break down the given absolute value equation into two separate equations.
x=- 3, x=1
When solving an equation involving absolute value expressions, we should consider what would happen if we removed the absolute value symbols. Let's look at an example equation. |ax+b|=|cx+d| Although we can make 4 statements about this equation, there are actually only two possible cases to consider.
Statement | Result |
---|---|
Both absolute values are positive. | ax+b=cx+d |
Both absolute values are negative. | -(ax+b)=-(cx+d) |
Only the left-hand side is negative. | -(ax+b)=cx+d |
Only the right-hand side is negative. | ax+b=-(cx+d) |
|x-3|=2|x| ⇔ |x-3|=|2x| Now let's consider these two cases for the given equation. Given Equation:& |x-3|=2|x| First Equation:& x-3 = 2x Second Equation:& x-3 =- 2x We will solve each of these equations by graphing separately.
To graph the first equation, we will create two functions out of the left- and right-hand sides of the equation. y=x-3 and y=2x The x-coordinate where the graphs of these functions intersect is the solution to our equation.
In order to graph the second equation, we will again create functions out of the left- and right-hand sides of the equation. y=x-3 and y=- 2x Once more, the x-coordinate where the graphs of these functions intersect is the solution to our equation.
x= 1
Subtract term
|1|=1
Identity Property of Multiplication
|-2|=2