Big Ideas Math Integrated I, 2016
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Big Ideas Math Integrated I, 2016 View details
6. Proving Triangle Congruence by ASA and AAS
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Exercise 18 Page 631

See solution.

Practice makes perfect

Using the Segment Addition Postulate, we can write the following two equations describing the length of AK and CJ: AK&=AJ+JK CJ&=KC+JK By the Reflexive Property of Congruence we know that JK ≅ JK. Additionally, the given information, AJ ≅ KC, allows us to, by the Substitution Property of Congruence, rewrite one of the equations: AK&= KC+JK CJ&=KC+JK Finally, using the Transitive Property of Equality we can show that AK=CJ. Thus, by the definition of congruence AK≅ CJ. Let's separate △ ABK and △ CBJ and add the information we have found.

Now we have enough information to prove congruence using the ASA Congruence Theorem.

Alternative Solution

Two-Column Proof
Let's show this as a two-column proof as well.

Statement
Reason
1.
&AJ≅ KC & ∠ BJK ≅ ∠ BKJ & ∠ A≅ ∠ C
1.
Given
2.
&AK=AJ+JK &CJ=KC+JK
2.
Segment Addition Postulate
3.
AJ=KC
3.
Definition of congruent segments
4.
&AK=KC+JK &CJ=KC+JK
4.
Substitution Property of Equality
5.
AK=CJ
5.
Transitive Property of Equality
6.
AK≅CJ
6.
Definition of congruent segments
7.
△ ABK ≅ △ CBJ
7.
ASA Congruence Theorem