Big Ideas Math Integrated I, 2016
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Big Ideas Math Integrated I, 2016 View details
6. Proving Triangle Congruence by ASA and AAS
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Exercise 17 Page 631

NL can be viewed as a transversal to QM and PL.

See solution.

Practice makes perfect

The given information tells us that M is the midpoint of NL. By the definition of a midpoint we can therefore say that NM≅ ML. Let's add this information to the diagram.

Also, we know that QM and PL are parallel lines. If we view NL as a transversal to these parallel lines, we can say by the Corresponding Angles Theorem that ∠ QMN and ∠ PLM are congruent.

Now we have enough information to claim the triangle are congruent by the ASA Congruence Theorem.

Alternative Solution

Two-Column Proof
Let's show this as as two-column proof as well.

Statement
Reason
1.
& M is the midpoint of NL &NL ⊥ NQ, NL ⊥ MP &QM ∥ PL
1.
Given
2.
∠ QNM and ∠ PML are right angles
2.
Definition of perpendicular lines
3.
∠ QNM ≅ ∠ PML
3.
Right Angles Congruence Theorem
4.
∠ QMN ≅ ∠ PLM
4.
Corresponding Angles Theorem
5.
NM ≅ ML
5.
Definition of midpoint
6.
△ NQM ≅ △ MPL
6.
ASA Congruence Theorem