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Solve one triangle at a time. Start with △ TUS.
m ∠ UTS = 26^(∘)
ST ≈ 9.1 m
TU ≈ 8.2 m
m ∠ VTW ≈ 39.7^(∘)
m ∠ TVW ≈ 50.3^(∘)
TW ≈ 10.9 m
Let's analyze the given right triangles.
We will solve each right triangle separately. We will start with △ TUS.
We will find the missing measures one at a time. In this case, this means that we want to find m ∠ UTS, ST, and TU.
Let's analyze △ TUS.
m ∠ UTS + 64 = 90 ⇔ m ∠ UTS = 26
Let x be the length of ST. We can find its value by using the cosine ratio.
Use a calculator
LHS * x=RHS* x
.LHS /(0.438371 ...).=.RHS /(0.438371 ...).
Round to 1 decimal place(s)
Since we already found the length of ST, we will first find the length of VT. VT=VS+ST ⇒ VT=5+9.1=14.1 As to the rest of the missing measures, we will find them one at a time. In this case, this means that we want to find m ∠ VTW, m ∠ TVW, and TW.
Let's analyze △ VTW. We can find m ∠ VTW using the sine ratio.
Use a calculator
Round to 1 decimal place(s)