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Big Ideas Math Geometry, 2014

BI

Big Ideas Math Geometry, 2014 View details

6. Solving Right Triangles

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Exercise 4 Page 505

The sine of an acute angle in a right triangle is the ratio of its opposite leg to the hypotenuse.

∠ A

Practice makes perfect

We want to determine which of the two acute angles in the given diagram has a sine of 511.

The sine of an acute angle in a right triangle is the ratio of its opposite leg to the hypotenuse. Let's calculate sin A and sin C.

sin =opposite/hypotenuse
sin A=BC/AC	sin C=AB/AC
sin A=5/11	sin C=4sqrt(6)/11

We can conclude that the acute angle that has a sine of 511 is ∠ A.

Subchapter links

Communicate Your Answer p.501

Monitoring Progress p.502-504