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High Tide: 6:00AM and 6:00PM
We want to write a sinusoidal model for the tide depth d at the port, as a function of the time t. To do so, we will consider the general forms of transformed sine and cosine functions. Sine Function:& y= asin b(t- h)+ k Cosine Function:& y= acos b(t- h)+ k In these functions | a| is the amplitude, 2Ď€ b is the period ( b>0), h is the horizontal shift, and k is the vertical shift. To write a function for a sinusoid, we will follow four steps.
Since the minimum point occurs at t=0, the function passes through y-axis at its minimum point. Then, the tide depth can be modeled as a cosine function reflected across the x-axis and with no horizontal shift. This means that h= 0.
Because of the location of the minimum point, we concluded that the tide depth should be modeled by a cosine function. We also found that a= - 6.5, b= π6, h= 0, and k= 10. Finally, we can write the equation of the model. d = - 6.5 cos π/6( t - 0)+ 10 ⇕ d=- 6.5 cos π/6 t + 10
Formula | |
---|---|
x-intercepts | (1/4*2Ď€/b,0), (3/4*2Ď€/b,0) |
Minimum | (0, a), (2Ď€/b, a ) |
Maximum | (1/2*2Ď€/b, - a) |
x-intercepts | Minimum | Maximum |
---|---|---|
(1/4*2Ď€/b, k), (3/4*2Ď€/b, k) | (0, a+ k), (2Ď€/b, a + k) | (1/2*2Ď€/b, - a+ k) |
(1/4*2Ď€/Ď€6, 10), (3/4*2Ď€/Ď€6, 10) | (0, - 6.5+ 10), (2Ď€/Ď€6, - 6.5+ 10 ) | (1/2*2Ď€/Ď€6, - ( - 6.5)+ 10) |
(3,10), (9,10) | (0,3.5), (12,3.5) | (6,16.5) |
Now we know five points that the given function passes through. Let's graph the function by plotting and connecting them with a smooth curve. Let's do it!
On the graph we can identify the maximum and minimum values of the function in a 24-hour period. These values will represent the high and the low tide at the port.
As we can see, the minimum is at 12 and 24 and the maximum is at 6 and 18. This means that the low tide is at 12:00AM and 12:00PM and the high tide is at 6:00AM and 6:00PM.
d=- 6.5 cos π/6t+ 10 ⇓ d=- 6.5 cos π/6(t + 3)+ 10 Let's show this on a coordinate plane!