Big Ideas Math Algebra 2, 2014
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Big Ideas Math Algebra 2, 2014 View details
6. Modeling with Trigonometric Functions
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Exercise 4 Page 508

The general forms of transformed sine and cosine functions are y=asin b(x-l)+k and y=a cos b(x-l)+k. Determine whether the graph is modeled by a sine or a cosine function, and then find the values of a, b, l, and k.

The amplitude and the vertical shift of the model are smaller.

Practice makes perfect

We know that a rope oscillates between 5 inches and 70 inches above the ground. We want to write a model for the height l of the rope as a function of time t. To do so, we will consider the general forms of transformed sine and cosine functions. Sine Function:& y= asin b(x- l)+ k Cosine Function:& y= acos b(x- l)+ k In these functions | a| is the amplitude, 2Ď€ b is the period ( b>0), l is the horizontal shift, and k is the vertical shift. To write a function of a sinusoid, we will follow four steps.

  1. Use the maximum and minimum values to identify any vertical shift k.
  2. Determine whether the model should be modeled by a sine or a cosine function, and identify any horizontal shift l.
  3. Find the period and the value of b.
  4. Find the amplitude and the value of a.

Let's follow these steps one at a time!

Step 1

The vertical shift k is the mean of the maximum and the minimum values. k=maximum value+ minimum value/2We know that the maximum value is 70 and the minimum value is 5. k=70+ 5/2 Let's evaluate this formula to find the value of k.
k = 70+5/2
k = 75/2
k= 37.5
We found that the vertical shift k is 37.5.

Step 2

Since the minimum value occurs at t=0, the function passes through y-axis at its minimum point. Then, the height can be modeled as a cosine function reflected across the x-axis and with no horizontal shift. This means that l= 0.

Step 3

Since the rope makes 2 revolutions per second, we know that it makes a complete revolution every 0.5 seconds. This means that the period is 0.5. Remember that the formula for a period of sine and cosine functions is 2Ď€ b. With this information, we can write an equation in terms of b. 0.5= 2Ď€/b Let's solve this equation!
0.5=2Ď€/b
â–Ľ
Solve for b
0.5b=2Ď€
1/2b = 2 π
b=4Ď€
We found that b= 4Ď€.

Step 4

Now, let's find the amplitude. This is half the difference between the maximum and the minimum values. | a| =maximum value- minimum value/2 In our case, the maximum value is 70 and the minimum value is 5. | a| = 70- 5/2 We will evaluate this formula to find the amplitude.
|a| = 70-5/2
|a| = 65/2
|a| = 32.5
Since the graph is a reflection in the x-axis of cosine function, we know that a<0. Therefore, a= - 32.5.

Equation of the Model

Because of the location of the minimum point, we concluded that the height should be modeled by a cosine function. We also found that a= - 32.5, b= 4π, l= 0, and k= 37.5. With this information, we can write the equation of the model. h(t) = - 32.5 cos 4π (t - 0)+ 37.5 ⇕ h(t)= - 32.5 cos 4πt + 37.5 Finally, we can compare it with the model given in the exercise. Original Model h(t) = - 36 cos 4πt + 39 [0.8em] New Model h(t) = - 32.5 cos 4πt + 37.5 Minimum and maximum values changed from 3 and 75 inches to 5 and 70 inches, which means that they are closer to each other. This makes the amplitude smaller. We can observe it in the equation of the model, the amplitude | a| = 32.5 in the new model is less than 36. Also, since the sum of minimum and maximum values decreased, the vertical shift k became smaller.