Big Ideas Math Algebra 2, 2014
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Big Ideas Math Algebra 2, 2014 View details
9. Modeling with Polynomial Functions
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Exercise 6 Page 223

Use the factored form of a cubic equation, f(x)=a(x-p)(x-q)(x-r), where p, q, and r are the x-intercepts.

f(x)=1/6(x+6)(x+3)(x-3)

Practice makes perfect
Using the general form of a factored cubic equation, we can write the factored form of the cubic function that passes through the given points. f(x)=a(x-p)(x-q)(x-r) In the above equation, p, q, and r are the x-intercepts of the function. We are told that the points ( - 6,0), (- 3,0), and (3,0) lie on the graph. Therefore, - 6, - 3, and 3 are roots of the equation. f(x)=a(x-( - 6))(x-(- 3))(x-3) ⇕ f(x)=a(x+6)(x+3)(x-3) Finally, we will find the value of a using the fact that the curve also passes through the point (0,- 9). We can substitute 0 for x and - 9 for f(x) in our equation with the roots.
f(x)=a(x+6)(x+3)(x-3)
- 9=a( 0+6)( 0+3)( 0-3)
â–Ľ
Solve for a
- 9=a(6)(3)(- 3)
- 9=- 54a
- 9/- 54=a
1/6=a
a=1/6
Now that we know that a= 16, we can write the full equation of the cubic function. f(x)=1/6(x+6)(x+3)(x-3)