Big Ideas Math Algebra 2, 2014
BI
Big Ideas Math Algebra 2, 2014 View details
9. Modeling with Polynomial Functions
Continue to next subchapter

Exercise 5 Page 223

Use the factored form of a cubic equation, f(x)=a(x-p)(x-q)(x-r), where p, q, and r are the x-intercepts.

f(x)=1/7(x+5)(x-1)(x-4)

Practice makes perfect
Using the general form of a factored cubic equation, we can write the factored form of the cubic function that passes through the given points. f(x)=a(x-p)(x-q)(x-r) In the above equation, p, q, and r are the x-intercepts of the function. We are told that the points ( - 5,0), (1,0), and (4,0) lie on the graph. Therefore, - 5, 1, and 4 are roots of the equation. f(x)=a(x-( - 5))(x-1)(x-4) ⇕ f(x)=a(x+5)(x-1)(x-4) Finally, we will find the value of a using the fact that the curve also passes through the point (2,- 2). We can substitute 2 for x and - 2 for f(x) in our equation with the roots.
f(x)=a(x+5)(x-1)(x-4)
- 2=a( 2+5)( 2-1)( 2-4)
â–Ľ
Solve for a
- 2=a(7)(1)(- 2)
- 2=- 14a
- 2/- 14=a
1/7=a
a=1/7
Now that we know that a= 17, we can write the full equation of the cubic function. f(x)=1/7(x+5)(x-1)(x-4)