Big Ideas Math Algebra 2, 2014
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Big Ideas Math Algebra 2, 2014 View details
9. Modeling with Polynomial Functions
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Exercise 4 Page 223

Use the factored form of a cubic equation, f(x)=a(x-p)(x-q)(x-r), where p, q, and r are the x-intercepts.

f(x)=(x+3)(x+1)(x-2)

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Using the general form of a factored cubic equation, we can write the factored form of the cubic function that passes through the given points. f(x)=a(x-p)(x-q)(x-r) In the above equation, p, q, and r are the x-intercepts of the function. We are told that the points ( - 3,0), (- 1,0), and (2,0) lie on the graph. Therefore, - 3, - 1, and 2 are roots of the equation. f(x)=a(x-( - 3))(x-(- 1))(x-2) ⇕ f(x)=a(x+3)(x+1)(x-2) Finally, we will find the value of a using the fact that the curve also passes through the point (- 2,4). We can substitute - 2 for x and 4 for f(x) in our equation with the roots.
f(x)=a(x+3)(x+1)(x-2)
4=a( - 2+3)( - 2+1)( - 2-2)
â–Ľ
Solve for a
4=a(1)(- 1)(- 4)
4=4a
1=a
a=1
Now that we know that a=1, we can write the full equation of the cubic function. f(x)=1(x+3)(x+1)(x-2) ⇕ f(x)=(x+3)(x+1)(x-2)