Exercise 7 Page 344

We are asked to write the first

6

terms of a sequence, given a recursive rule.

a_{1} a_{n} = 0 = a_{n - 1} + 2, for n \geq 2

To do so, we will use a table.

$n$	$a_{n} = a_{n - 1} + 2$	$a_{n - 1} + 2$	$a_{n}$
$1$	$a_{1} = 0$	$-$	$0$
$2$	$a_{2} = a_{2 - 1} + 2$	$a_{1} + 2 = 0 + 2$	$2$
$3$	$a_{3} = a_{3 - 1} + 2$	$a_{2} + 2 = 2 + 2$	$4$
$4$	$a_{4} = a_{4 - 1} + 2$	$a_{3} + 2 = 4 + 2$	$6$
$5$	$a_{5} = a_{5 - 1} + 2$	$a_{4} + 2 = 6 + 2$	$8$
$6$	$a_{6} = a_{6 - 1} + 2$	$a_{5} + 2 = 8 + 2$	$10$

Therefore, the first $6$ terms of the sequence are $0,$ $2,$ $4,$ $6,$ $8,$ and $10 .$ Let's graph these points!