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This lesson provides an in-depth look at adding and subtracting linear expressions, a fundamental skill in algebra. It uses real-world examples, such as Dominika and Magdalena's competition scores and Ignacio's weekend laundry, to demonstrate how these mathematical operations can be applied in everyday life. The lesson emphasizes the importance of combining like terms and distributing negative signs correctly when performing these operations. It also explains the concept of linear terms and constant terms, which are crucial for understanding linear expressions. The aim is to equip you with the skills needed to simplify and manipulate linear expressions, whether for academic purposes or real-world problem-solving.
Show less Show more expand_more| Student Learning Objectives: |
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| | 9 Theory slides |
| | 10 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
Dominika really enjoys longboard dancing. She decided to go to the local skate shop to buy some supplies for an upcoming competition.
Dominika used her receipt to write out what she spent as two algebraic expressions. Maybe her math teacher will give her extra credit when she shows it to him!
On her way to the park to practice, Dominika wondered how to combine the expressions to represent the total she spent at the store.
Write an expression for her total expenses.
A linear term is an algebraic expression that includes a coefficient multiplied by a variable with an exponent of 1. A linear expression is an expression that includes at least one linear term and any constant terms. No other type of terms may be included.
Determine whether the given expression is a linear expression.
The process of adding or subtracting linear expressions is similar to performing those operations on numbers. Consider two linear expressions. Expression One: &2x + 11 Expression Two: &3x - 7 Let's add and subtract these expressions.
To add two linear expressions, follow the same process as adding two numbers. (2x + 11)+(3x - 7) ⇓ 2x + 11+3x - 7 The result is an expression with two x-terms and two constants. Next, pair up these terms into two sets of like terms. Finally, combine each pair of like terms and simplify.
Commutative Property of Addition
Add terms
Subtract terms
When writing the subtrahend expression, it is important to distribute the negative sign to change each of terms in the subtrahend expression to its additive inverse. (2x + 11)-(3x - 7) ⇓ 2x + 11-3x + 7 Next, group like terms and simplify the expression.
Commutative Property of Addition
Subtract terms
Add terms
Dominika met up with her friends over the weekend to practice for the competition.
She documented her practice times using linear expressions.
| Day | Practice Time (min) |
|---|---|
| Friday | 4t+32 |
| Saturday | 7t+26 |
| Sunday | 3t-15 |
Write an expression for her total practice time on Friday and Saturday.
Dominika and her friends practiced longer on Saturday than on Sunday. How much longer did Dominika and her friends practice on Saturday than on Sunday?
Add the expressions for the practice times on Friday and Saturday.
Subtract the expression representing Sunday's practice time from the expression for Saturday's practice time.
Add the practice time from each day to write the total practice time for Friday and Saturday.
Friday's Practice Time + Saturday's Practice Time The corresponding expressions can be found in the given table.
| Day | Practice Time (min) |
|---|---|
| Friday | 4t+32 |
| Saturday | 7t+26 |
| Sunday | 3t-15 |
After finding the sum, we will simplify the expression by combining the like terms.
Substitute expressions
Commutative Property of Addition
Add terms
Dominika and her friends practiced for 11t+58 minutes in total on Friday and Saturday.
This time Sunday's practice time will be subtracted from Saturday's.
Saturday's Practice Time - Sunday's Practice Time The corresponding expressions can be found in the given table.
| Day | Practice Time (min) |
|---|---|
| Friday | 4t+32 |
| Saturday | 7t+26 |
| Sunday | 3t-15 |
When subtracting, remember to distribute the negative sign before combining the expressions!
Substitute expressions
Distribute -1
Commutative Property of Addition
Subtract terms
Add terms
Dominika and her friends practiced for 4t+41 minutes longer on Saturday than on Sunday.
It's finally time for the longboard dance competition!
Each participant's score is given by adding the two best scores from three rounds. Dominika wrote her final score as an expression. Dominika's Final Score 3x+2y+12 Dominika is really proud of her score and she thinks that she can win. After seeing her friend Magdalena perform, though, Dominika starts thinking that maybe Magdalena might win.
| Magdalena's Two Best Scores | |
|---|---|
| 2x+y+7 | x+y+6 |
In the end, Dominika and Magdalena placed in the top two positions of the competition.
Write a simplified expression for the difference between Dominika's and Magdalena's scores.
Who won first place?
Subtract the sum of Magdalena's scores from Dominika's score.
Can we tell who has the higher score?
The difference between Dominika's and Magdalena's final scores can be found by subtracting Magdalena's final score from Dominika's score.
Dominika's Final Score - Magdalena's Final Score Magdalena's final score is not given but we know it can be found by adding her two best scores. Then the difference between the girls' scores can be written as an expression. 3x+2y+12 - ( 2x+y+7 + x+y+6) Here we are subtracting the sum of two linear expressions from another linear expression. Remember that the order of operations must be followed — this means that the expressions between parentheses are simplified first by combining the like terms.
Commutative Property of Addition
Add terms
Magdalena's final score is 3x+2y+13. Let's subtract this score from Dominika's final score.
Distribute -1
Commutative Property of Addition
Subtract terms
The difference between their scores is -1. They are really close!
In Part A, we found that subtracting Magdalena's final score from Dominika's score results in -1.
Dominika's Final Score - Magdalena's Final Score ⇓ -1 This means that Magdalena's score is slightly higher than Dominika's. Since the girls won the top two places, Magdalena won the first place. First Place: & Magdalena Second Place: & Dominika Dominika did not win first place in the competition, but she is really proud of herself for winning second place and being so close. Now she is motivated to practice and get even better!
Add or subtract the given linear expressions.
Earlier in this lesson, Dominika wrote a couple of expressions to show how much money she spent buying equipment for the competition.
Dominika wants to combine the expressions to find one that reflected how much money she spent in total. Notice that the expressions she wrote are linear expressions. To add them, group the like terms and combine them.
This means that Dominika spent $8x+9 in total when buying the equipment. She is really dedicated to longboard dancing!
Add the following linear expressions. m+11 m-7
We can write a new expression by adding the two given linear expressions. (m+11)+(m-7) ⇓ m+11+m-7 Now we need to simplify this expression. The first step in simplifying this expression is to identify which, if any, terms can be combined. Remember, only like terms — constant terms or terms with the same variable — can be combined. m + 11 + m - 7 In this case, we can see two m-terms and two constants. Both of these pairs can be combined. We will apply the Commutative Property of Addition to group the like terms together and then combine them by adding or subtracting.
The expression is now simplified. Good job!
Consider the following linear expressions. 6-7n -16n+3 Subtract the second expression from the first expression.
We can write a new expression by subtracting the two given linear expressions. Remember that we need to distribute the negative sign to replace every term of the subtrahend expression by its corresponding additive inverse. (6-7n)-(-16n+3) ⇓ 6-7n + 16n - 3 Now we need to simplify this expression. The first step in simplifying this expression is to identify which, if any, terms can be combined. Remember, only like terms — constant terms or terms with the same variable — can be combined. 6 - 7n + 16n - 3 In this case, we can see two n-terms and two constants. Both of these pairs can be combined. We will apply the Commutative Property of Addition to group the like terms together and then combine them by adding or subtracting.
Now the expression is simplified. Good job! Remember that we can apply the Commutative Property of Addition again to rewrite this expression if we want. 3+9n ⇓ 9n+3
Ignacio is almost out of clean clothes. Because of this, he decided to do the laundry during the weekend.
On Saturday, Ignacio washed 3c+1 pounds of laundry. On Sunday, he did 5c-2 pounds. How many pounds of laundry did he do over the weekend?
We want to find how many pounds of laundry Ignacio washed over the weekend. We can find this by adding the pounds washed from Saturday and Sunday. Saturday's Laundry + Sunday's Laundry We are given these quantities as linear expressions. Saturday's Laundry + Sunday's Laundry ⇓ 3c+1 + 5c-2 If we add them together, we have an expression for the total laundry. However, we can simplify it to write it more compactly. First, let's identify the like terms. 3c + 1 + 5c - 2 We can see that there are two c-terms and two constants. Both of these pairs of like terms can be combined. Let's apply the Commutative Property of Addition to group the terms, then combine them by adding or subtracting.
This means that Ignacio did 8c-1 pounds of laundry during the weekend. We did it!
Izabella has been training for a marathon, but she wants to be more consistent with her training. She ran different distances on Friday and on Saturday. Friday Miles: &3m+1 Saturday Miles:&2m+5 Write and simplify an expression for the difference between the distances that Izabella ran on Friday and on Saturday.
We want to find the difference between the distances Izabella ran on Friday and Saturday. This difference is found by subtracting the miles run from each day. Friday Miles- Saturday Miles We are given these miles as linear expressions. Let's substitute them to write the expression for the difference. Friday Miles- Saturday Miles ⇓ 3m+1 - ( 2m+5 ) Now we have an expression for the difference. This is great progress! Let's simplify it. To start, we will distribute the negative sign and identify the like terms — terms with the same variables raised to the same power. 3m+1 - (2m+5 ) ⇓ 3m + 1 - 2m - 5 We can see that there are two m-terms and two constants. These terms can be grouped using the Commutative Property of Addition and combined by adding or subtracting.
The difference between the distances Izabella ran on Friday and Saturday was m-4 miles.
Tiffaniqua followed these three steps to subtract two linear expressions.
Which step did Tiffaniqua make a mistake in?
Let's subtract the linear expressions ourselves to identify whether Tiffaniqua made a mistake. We can begin by distributing the negative sign to replace every term in the expression being subtracted with its additive inverse. (x+1)-(x+3) = x+1 -x - 3 After distributing the negative sign, we can see that the 3 is being subtracted. When Tiffaniqua did the subtraction, she added the 3. This means that Tiffaniqua made a mistake in Step 1. Let's continue solving to see the real result.
The correct result of the subtraction is -2.