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| 12 Theory slides |
| 11 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Izabella's favorite candy, Frutty, is sold in packs of thirty candies with three different flavors — apple, orange, and banana.
Begin by finding the range of the data, then draw a number line which covers this range.
The smallest number in the data set is 8 and the largest is 12. This means that the dot plot can be displayed above a horizontal number line that covers at least the numbers from 8 to 12. Here, a number line from 7 to 13 will be used.
From here, the dot plot can be drawn as follows.
A multiple-choice test has ten questions. After grading the test, the teacher produced the following dot plot to show how many correct answers each student had on the test.
How many students are there in the class?
Each dot represents the performance of one student on the test.
Each dot represents the performance of a student on the test. For example, since there is one dot above the number 4, it means that one student answered four questions correctly. The rest of the dot plot can be interpreted similarly.
Number | Dots Above the Number | Conclusion |
---|---|---|
0,1,2,3 | 0 | There are no students who answered fewer than four questions correctly. |
4 | 1 | One student answered four questions correctly. |
5 | 3 | Three students answered five questions correctly. |
6 | 2 | Two students answered six questions correctly. |
7 | 4 | Four students answered seven questions correctly. |
8 | 5 | Five students answered eight questions correctly. |
9 | 3 | Three students answered nine questions correctly. |
10 | 2 | Two students answered all ten questions correctly. |
A college hockey team played 23 games during a season. An enthusiastic fan made a dot plot of the number of goals the team scored in each game.
Group the data in a frequency table using the intervals asked in the prompt. The first interval will be the ages 40–44.
The frequency table below shows the grouping of the data starting at 40 and using 5-year intervals.
Interval | Frequency |
---|---|
40–44 | 2 |
45–49 | 7 |
50–54 | 12 |
55–59 | 13 |
60–64 | 8 |
65–69 | 2 |
70–74 | 1 |
Use these intervals and frequencies to draw the histogram.
In 1936, Sir Ronald Aymler Fisher published a paper entitled The Use of Multiple Measurements in Taxonomic Problems.
Fisher investigated several measurements of three species of flowers.
The histogram below shows the summary of the data about the sepal length of the Iris virginica flowers.
How many Iris Virginica flowers did Fisher investigate in this paper?
Consider the height of the rectangles in the histogram.
In a histogram, the height of the rectangles shows the frequency of the data elements in the corresponding interval.
A ranger is surveying a forest. He randomly selected 40 loblolly pines (Pinus taeda) and measured their heights. The histogram below is the summary of the data.
Rearrange the data in increasing order and find the five-number summary.
The box-plot is built using these points.
Putting all this together gives the box plot.
In the 1994 report The Population Biology of Abalone (Haliotis species) in Tasmania,
the authors presented and investigated the measurements of 4177 blacklip abalones.
The lengths of the shells in millimeters are summarized in the box plot below.
How many blacklip abalones' lengths were shorter than 90 millimeters in this experiment?
Which part of the box plot is at 90?
The left side of the box is at 90, so the first quartile of the lengths is 90 millimeters.
Note that from the box plot, the only conclusion we can make is that the number of blacklip abalones shorter than 90 millimeters is less than 1045.
In fact, there were 60 blacklip abalones with a length of 90 millimeters in the experiment. The answer option 1007 reflects the actual answer to the question, but to get this value, the full data is needed — the box plot is not enough.
The heights, in feet, of red alder (Alnus rubra) trees in a forest are summarized in the following box plot.
In some cases, scientists use visual representations that go beyond the three types of plots discussed in this lesson. For example, the report about the blacklip abalones also contains data about their sex. This can be used to present a summary of the length in a stacked histogram.
Ignacio is a math teacher. On Friday, he gave a pop quiz to each of his classes and plans to give the results to each class on Monday. On Friday night, he wrote the results for each class on different paper slips that look like the following image. He also made dot plots to match each paper slip.
He ran into a huge problem over the weekend — he left the paper slips in his pocket while doing laundry! The box plots are safe, but only the paper slip above still shows the results. That sole surviving paper slip matches one of the following box plots.
To draw the dot plot, we must count the number of times each observation occurs. To make this easier, we can start by arranging the data set in ascending order. 7,7,8,8,8,8,9,9,9,10,10,10,10,11 Now we will count how many times each observation occurs. |c|c| Value & # of Observations 7 & 2 8 & 4 9 & 3 10 & 4 11& 1 The number of observations of a value is represented by the number of dots over that value. For example, over the value 7, there should be 2 dots.
Compare this dot plot to the options. It matches with A.
To determine which is the correct dot plot, let's draw the one corresponding to the given data. To do so, we will count the number of times that each observation occurs. |c|c| Value & # of observations 0 & 3 1 & 2 3 & 1 5& 3 6& 3 7& 2 8& 1 When we draw the dot plot, we will let the number of observations of a certain value be represented by the number of dots over that value. For example, over the value 0 we place 3 dots.
If we compare this dot plot to the alternatives, we see that it matches with C.
To determine which is the correct box plot, let's draw the one corresponding to the given data set. Find the following information. Minimum Value Lower Quartile Median Upper Quartile Maximum Value These values are more clear to find when the set is written in ascending order. Luckily, it already is. Let's begin and determine the median. This is the middle value of the data set.
Since the data set has 11 observations, which is an odd number, the 6^(th) observation must be the median. We will then have an equal number of observations on the left and right sides of the median.
It helps to organize the values in a table. |c|c| [-0.8em] Observation(s) & Data [0.3em] [-0.8em] 1^(st) - 5^(th) & 4.0, 5.2, 6.0, 7.0, 7.1 [0.3em] [-0.8em] Median & 8.0 [0.3em] [-0.8em] 7^(th) - 11^(th) & 8.2, 8.8, 9.0, 12.0, 13.0 [0.3em]
Next, determine the lower and upper quartile by finding the middle observation of the values that are to the left and right of the median. Since the number of observations in each half is odd, the quartiles will be the third and ninth observations, respectively.
Reorganize the table to show the quartiles. This table also shows the minimum and maximum values. |c|c| [-0.8em] Observation(s) & Data [0.3em] [-0.8em] Minimum Value & 4.0 [0.3em] [-0.8em] 2^(nd) & 5.2 [0.3em] [-0.8em] Lower Quartile & 6.0 [0.3em] [-0.8em] 4^(th) and 5^(th) & 7.0, 7.1 [0.3em] [-0.8em] Median & 8.0 [0.3em] [-0.8em] 7^(th) and 8^(th) & 8.2, 8.8 [0.3em] [-0.8em] Upper Quartile & 9.0 [0.3em] [-0.8em] 10^(th) & 12.0 [0.3em] [-0.8em] Maximum Value & 13.0 [0.3em]
Use the values in the table to draw the box plot.
Finally, compare this box plot with the four given ones. The correct option is C.
A chain of restaurants called Wing Wings is known for their tasty chicken wings, of course. It is their secret sauce that makes them both super tasty and have a high calorie count. A dietitian, who wants to bring down the chain, analyzed one wing every day for 31 consecutive days.
Which of the following histograms represents the data collected by the dietitian?
To determine which is the correct histogram, let's draw the one representing the data collected by the dietitian. To do this, first, let's organize the data in a table starting at 120 and with intervals of 20.
Interval | Observations | Count |
---|---|---|
120-140 | 121.2, 125.7, 126.2, 126.9, 128.2, 135.7, 139.7 |
7 |
140-160 | 141.8, 143.0, 143.8, 146.3, 147.4, 147.6, 152.8, 155.2, 156.7, 157.0, 157.0 |
11 |
160-180 | 160.5, 163.3, 169.5, 170.7, 170.8, 173.2, 173.5 |
7 |
180-200 | 180.1, 181.4, 184.5, 196.1 | 4 |
200-220 | 0 | |
220-240 | 0 | |
240-260 | 0 | |
260-280 | 261.0, 275.0 | 2 |
Now that we know the number of observations in each interval, we can draw the histogram.
Comparing this histogram with the given options, the correct choice is B.
Consider the following box plot.
Use the box plot to find the required measure.
The least value, or minimum value, of a box plot is given by the end of the left whisker.
As we can see, the minimum value is 1.
The greatest value, or maximum value, is given by the end of the right whisker of the box plot.
The maximum value is 10.
The third quartile in a box plot is marked by the end of the box. The third quartile is also written as Q_3.
As we can see, the third quartile is 5.
The first quartile of a box plot is marked by the start of the box. The first quartile can also be written as Q_1.
The first quartile is 2.
The median of a box plot is given by the vertical line that is found inside of the box.
The median is 4.
Kris is a high school student who is thinking about which classes to take. The boxplot below represents the number of students in each class.
The number of classes that Kriz is taking is given by the number of dots in the dot plot. Let's count them.
By adding the number of observations, we can determine how many classes Kriz is taking. 2+3+4+1+1+1=12 Kriz is taking 12 classes.
The greatest number of students is given by the observation we find furthest to the right in the dot plot.
The greatest number of students is 26.
The most common number of students in the classes is the value with the greatest number of observations in the dot plot.
The most common number of students is 22.
To calculate the average number of students per class we must divide the total number of students in all of his classes with the number of classes. Average=Number of students/Number of classes Therefore, we must first add up the number of students.
Now we can calculate the average.
The average number of students per class is 22.