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When lines are parallel, they have the same slope. Consider the given line, which is written in slope-intercept form.
$y=3x−1y=mx+b $
In the given equation we can see that the slope of the line is $3.$ Thus, our equation must have the slope $3$ as well.
$y=3x+b $
To complete the equation, we must find the $y$-intercept $b.$ It can be found by substituting $(x,y)$ with our point $(-2,2).$
Now that we know that $b=8,$ we can write the equation of the line.
$y=3x+8 $

$y=3x+b$

$2=3(-2)+b$

Solve for $b$

$b=8$