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| 12 Theory slides |
| 10 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here is some recommended reading before getting started with this lesson.
From the exploration, the following conclusions can be drawn.
To perform a translation, a vector is required. This implies that the direction of the translation plays an important role. To illustrate this statement, consider the following diagram.
Consequently, and referring to what can be inferred from the exploration applet, a third conclusion can be drawn.
The vectors AA′, BB′, and CC′ have the same direction as v.
Be aware that the three conclusions written before do not depend on the preimage. They hold true even when the preimage is a single point, a segment, a polygon, or any other figure. Then, these properties can be used to define a translation properly.
A translation is a transformation that moves every point of a figure the same distance in the same direction. More precisely, a translation along a vector v maps every point A in the plane onto its image A′ such that the following statements hold true.
As the previous exploration shows, translations preserve side lengths and angle measures. That confirms translations are rigid motions. Additionally, take note that translations map segments onto parallel segments. Consider the polygon P shown in the middle of the diagram below. The other polygons are images of P after different transformations.
What polygons are the image of P after a translation?
Only polygons P4, P6, and P14 are the image of P after a translation.
Remember that translations map segments onto parallel segments. Since P looks like an arrow pointing up, the images of P after a translation will also look like an arrow pointing up.
Since translations map segments onto parallel segments, the sides of P are parallel to the sides of its image after any translation. Notice that P looks like an arrow pointing up.
In the previous example, only the shape of polygon P was used to determine which polygons were the image of P after a translation. When the vertices are labeled, keep an eye on them. Consider the following three squares.
Therefore, S2 is not the image of PQRS after a translation. Conversely, S1 satisfies the two conditions previously written. Even more, since every vector that connects a vertex to its image have the same direction, it can be concluded that S1 is a translation of PQRS.
Translations can be performed by hand with the help of a straightedge and a compass.
To translate △ABC along v follow the four steps below.
Draw parallel lines to ℓ through each vertex.
Draw the triangle formed by the image points A′, B′, and C′.
By definition of translation, vectors AA′ and v are parallel and have the same magnitude and direction. This makes PAA′Q a parallelogram. With this in mind, the translation of △ABC can be performed as follows.
In the following applet, one of the following tasks may be required.
To translate △ABC, place points A′, B′, and C′ where they should be after the translation is applied.
When learning about rotations, it was said that the composition of two rotations could be a translation. Now, the composition of two translations will be examined.
Consider the following pair of quadrilaterals P1 and P2. Also, consider a pair of different translations. One translation along vector u=⟨5,1⟩ and the other along v=⟨-2,-4⟩.
Translating Along | Is Equivalent To |
---|---|
u=⟨5,1⟩ | Translating 5 units to the right and 1 unit up. |
v=⟨-2,-4⟩ | Translating 2 units to the left and 4 unit down. |
All the vectors drawn seem to be parallel and with the same magnitude. Even more, they all have the same direction. This could be checked by finding the component form of each vector.
Vertex | Image | Vector | Component Form |
---|---|---|---|
(-4,0) | (-1,-3) | ⟨-1−(-4),-3−0⟩ | ⟨3,-3⟩ |
(-1,1) | (2,-2) | ⟨2−(-1),-2−1⟩ | ⟨3,-3⟩ |
(-1,2) | (2,-1) | ⟨2−(-1),-1−2⟩ | ⟨3,-3⟩ |
(-3,3) | (0,0) | ⟨0−(-3),0−3⟩ | ⟨3,-3⟩ |
As the table shows, all the vectors connecting a preimage with its image have the same component form. This confirms that the vectors are parallel and have the same magnitude and direction. Consequently, a translation along ⟨3,-3⟩ maps P1 onto P2.
The two conclusions obtained in the previous example are not a coincidence. In fact, these are general results when performing a composition of translations.
Be aware that a composition of transformations might involve translations and rotations. This combination can produce interesting images.
In interior design, it is pretty common to see designs consisting of a single preimage and its images under different transformations such as translations and rotations. Below, two different kitchen tile designs are made using just four right triangles.
Translate point P(2,5) according to the vector. What are the coordinates of the resulting image?
The vector form tells us how we should move in the coordinate plane. Vector Form: ⟨ 6, 0 ⟩ Horizontal translation:& + 6units Vertical translation:& 0units Let's plot point P in a coordinate plane and move it according to the vector form. Notice that we only have to perform a horizontal translation to the right of 6 units.
The image of P has the coordinates P'(8,5).
Like in Part A, we will analyze the vector form to determine how to move P. Vector Form: ⟨ 5, -1 ⟩ Horizontal translation:& + 5units Vertical translation:& - 1unit Let's move P according to the vector form. This time we must perform both a horizontal and a vertical translation.
As we can see, the image of P has the coordinates P'(7,4).
Like in previous parts, we will determine how P must move according to the vector form. Vector Form: ⟨ -8, -7 ⟩ Horizontal translation:& -8units Vertical translation:& - 7units If we move the point 3 units to the left and 7 units down we find P'.
Examining the coordinate plane, we see that P' has the coordinates (-6,-2).
Translate the given point P using vector v. What are the coordinates of the image P′?
To translate P in the direction of the vector, we will move v until its starting point has the same coordinates as P. At the end of v, we will then find P'.
The coordinates of P' are (8,6).
As in Part A, we will translate the vector so that it starts at P. The endpoint of the vector tells us where the coordinates of the image is.
The image P' has the coordinates (8,4).
As in previous parts, v must be translated until its starting point is at P. Then we can find the coordinates of P' at the end of v.
The coordinates of P' are (5,5).
In the following pattern, two figures represent translations of each other. Can you tell which ones?
A translation is a rigid motion that preserves the lengths and angle measures of a figure. Therefore, what we are looking for are two shapes that have exactly the same shape and orientation. There are only two such shapes: E and G. These can be translated across the grid and map onto each other.
A construction worker wants to use her front-end loader to move some debris on a construction site. In relation to the entry point of the construction site (0,0), the debris is at (11,1). The worker moves it through the construction site along the vectors ⟨-6,3⟩, ⟨-3,3⟩, and ⟨7,2⟩. This gets her to the spot where she unloads the debris.
Let's start by plotting the point where the debris is.
Next, we will determine the vertical and horizontal movements for the three vectors, which we will label v_1, v_2, and v_3. v_1 = ⟨ - 6, 3 ⟩ Horizontal translation:& - 6units Vertical translation:& +3units v_2 = ⟨ - 3, 3 ⟩ Horizontal translation:& - 3units Vertical translation:& + 3units v_3 = ⟨ 7, 2 ⟩ Horizontal translation:& +7units Vertical translation:& +2units Now we can illustrate the movements of the front-end loader.
The debris is dropped off at (9,9).
From Part A, we know the points where the debris is picked up and where it is unloaded.
A single vector that describes the movement of the front-end loader is the vertical and horizontal difference between these points.
The vector can be written as ⟨ - 2,8 ⟩.
Which of the polygon(s), A through E, are translations of Q?
A translation changes a polygon's position but preserves shape, size, and orientation. Examining the five polygons, we see that A has a different size and B has a different shape. Therefore, neither can be translations of Q. Let's remove them.
The remaining polygons all have the same shape and size. However, we see that E has a different orientation. It is facing the wrong direction. Therefore, E can not be a translation of Q either. Let's remove it.
Let's attempt to translate Q and make it map onto C and D. If it does, C and D are translations of Q.
As we can see, C and D are both translations of Q.